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3 years ago

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Write a CER to explain what happened to this styrofoam head. The pics are of the head above water, at a depth of 1000m underwate

r, and at 3000 m underwater. Talk about the gas laws and/or KMT in your reasoning section!

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

what is that i connot understand your question

Explanation:

im sorry i connot answer your question

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If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

50

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

$\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}$

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

$\text{Moles of NO}_{2} = \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

$\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}$

(b) Mass of NO reacted

$\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}$

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

5 0

3 years ago

Which element is most common in sea water?

SVEN [57.7K]

Answer:

The answer is (B.) Chlorine

Explanation:

Its because i took the test

4 0

3 years ago

The best methdos for separating an. mixture a solution is to use

vaieri [72.5K]

Answer:

Filtration method

Explanation:

This method is the most easy method to separate a mixture

3 0

2 years ago

Deduce the total rate change of momentum of a cylinderical shaped object

Ugo [173]

Rotational versus translational kinetic energy; Total kinetic energy; Acceleration of a rolling object. Example scenarios. Rolling cylinders.

8 0

2 years ago

Refer to the reaction between magnesium and oxygen In the introduction. What elements is oxidizing?write the oxidation number fo

erica [24]

Answer:

Oxidizing element: Mg

Explanation:

Reaction of magnesium and oxygen can be written as:

$2Mg +O_2 \rightarrow 2MgO$

while writting chemical reaction between two atom or element then write their natural form i.e. how that atom or element exist in the nature.

eg. reaction of any element with Oxygen atom then we can not write directly O because oxygen exist in the nature in form of $O_2$

finding oxidation number each side:

Reactant side:

Mg=0;

O=0;

product side:

Mg=+2;

O=-2;

from above:

oxidation number of Mg is increasing hence this is oxidizing element

7 0

2 years ago