Answer:
The numerical length of JL is 6 units
Step-by-step explanation:
Here, we want to determine the numerical length of JL
Mathematically;
JL = JK + KL
2x + 8 = 5x + 7 + 4
2x + 8 = 5x + 11
5x -2x = 8-11
3x = -3
x = -1
But JL = 2x + 8
JL = 2(-1) + 8 = -2 + 8 = 6
2y + 12 = -3x
Step-by-step explanation:
Divide y y by 1 1 . Divide 12 12 by 2 2 . Use the slope-intercept form to find the slope and y-intercept. The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept.
Solution to the system of equation (-2,5)
Answer:
Step-by-step explanation:
3y+7=2x
3y=2x-7
y=(2/3)x-7/3
when parallel, the y=ax+b, the a keeps the same
so it‘s y=(2/3)x-a
and it pass (2,6), so 6=(2/3)*2 -a
6=4/3-a
-a=(18-4)/3
-a=14/3
a=-14/3
Answer:
Hello your question is poorly written attached below is the complete question
answer : attached below
Step-by-step explanation:
To Prove: Z is located 2/3 of the distance from each vertex of ΔABC to the midpoint of the opposite side. we will apply ; property of bisecting a line , equality theorem , transitive property and similarity theorem
Attached below is the proof
