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____ [38]
3 years ago
7

Step 7: Determine the Limiting Reactant (Trial 2)

Chemistry
1 answer:
otez555 [7]3 years ago
8 0

Answer:

aluminum

no aluminum is left over

Explanation:

the next answers for step 7 are 0.019, 0.0093, aluminum

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What mass of water is required to react completely with 157.35 g CO2? (Molar mass of H2O = 18.02 g/mol; molar mass of CO2 = 44.0
Ghella [55]

You must use 64.43 g H₂O.

<em>Balanced chemical equation</em>: H₂O + CO₂ → H₂CO₃

<em>Moles of CO₂</em> = 157.35 g CO₂ × (1 mol CO₂/44.01 g CO₂) = 3.5753 mol CO₂

<em>Moles of H₂O</em> = 3.5753 mol CO₂ × (1 mol H₂O/1 mol CO₂) = 3.5753 mol Fe

<em>Mass of H₂O</em> = 3.5753 mol H₂O × (18.02 g H₂O /1 mol H₂O) = 64.43 g H₂O

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Cells are the fundamental units of life ' the bricks from which all your. which are built of your cells, will become compromised, and you can. of these new cells from the nutrients you get in your food is one way. Let's take a look inside one of your cells and see what the nutrients really do.

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Which way of dissolving changes the chemical identity of the solute?
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Consider the reaction of 19.0 g of zinc metal with excess silver nitrate to produce silver metal and zinc nitrate. The reaction
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14.5 g silver

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This is a problem using the stoichiometry of the reaction. First thing we need is the balanced equation:

   Zn + 2 AgNO3 ----------------------- 2 Ag + Zn(NO3)2

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0.135 mol Ag x  107.9 g/mol = 14.5 g Ag

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3 years ago
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