E=hf
h=6.63*10^-34
f=8.66*10^14
E=6.63*10^-34*8.66*10^14=57.4*10^-20 joules
Answer:
~69.744 moles of Ca
Explanation:
Using Avogadro's constant , we know that:
1 mole = 6.022 x 10^23 atoms
S0, the number of moles in 4.20 x 10^25 atoms of Ca:
=(4.20 x 10^25 x 1 )/(6.022 x 10^23)
~69.744 moles of Ca
Q2:How many atoms are in 0.35 moles of oxygen?
1 mole = 6.022 x 10^23 atoms
S0, the number of atoms in 0.35 moles of oxygen:
=[0.35 x (6.022 x 10^23)]
=2.1077 x 10^23 atoms of Oxygen
Hope it helps:)
Answer:
the number of protons is called the atomic number
hope it helps you buddy
Answer:
The plum pudding model of the atom agreed with the nuclear model
Explanation:
