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denis23 [38]
3 years ago
6

Meeet.gooogle.com/ttp-wdqt-pad

Chemistry
2 answers:
Serhud [2]3 years ago
4 0
I can teach you English
matrenka [14]3 years ago
3 0
I can also teach you English. I also know Spanish and French.
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True or false ? <br>an insoluble base will react with an acid. <br>​
Leno4ka [110]

Answer:

true maybe

Explanation:

#CarryOnLearning

7 0
3 years ago
Liquid octane (CH) has a density of 0.7025 g/mL at 20 °C. Find the true mass (murue) of octane when the mass weighed in 18 air i
Goshia [24]

Explanation:

According to Buoyance equation,

          m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]

where,      m = true mass

                 m' = mass read from the balance = 17.320 g

              d_{a} = density of air = 0.0012 g/ml

              d_{w} = density of the balance = 7.5 g/ml

                    d = density of liquid octane = 0.7025 g/ml

Now, putting all the given values into the above formula and calculate the true mass as follows.

      m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]    

          = [17.320 g \times \frac{1 - \frac{0.0012 g/ml}{7.5 g/ml}}{1 - \frac{0.0012 g/ml}{0.7025}}]

          = 17.320 g \times 0.999850                

          = 17.317 g

Thus, we can conclude that the true mass of octane is 17.317 g.

7 0
3 years ago
A food processing plant discharges 40 cfs (cubic feet per second) of process water containing an ultimate BOD (L0) of 25 mg/L an
Feliz [49]

Answer:

The right solution according to the question is provided below.

Explanation:

According to the question,

(a)

The initial conditions will be:

DO = \frac{(40\times 1.8)+(260\times 7.6)}{40+260}

      = \frac{2048}{300}

      = 6.826 \ mg/L

The initial oxygen defict will be:

Do = 8.5-6.826

     = 1.674 \ mg/L

The initial BOD will be:

Lo = \frac{(40\times 25)+(260\times 3.6)}{40+260}

    = \frac{1936}{300}

    = 6.453 \ mg/L

(b)

The time reach minimum DO:

tc = \frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}

   = \frac{1}{0.15}\times ln \ 1.158

By putting the values of log, we get

   = 0.973 \ days

The distance to reach minimum DO will be:

Xc = \frac{1.1\times 3600\times 24}{5280}\times 0.973 \ days

    = 18\times 0.973

    = 17.5 \ miles

8 0
3 years ago
______collisions describe the process by which particles collide and transfer energy without loss of energy.
Elina [12.6K]

Answer:

A. Elastic

Explanation:

an elastic collision is one which there is no overall loss of kinetic energy

5 0
3 years ago
Which one is a compound
zheka24 [161]

Answer:

CO

Explanation:

the rest are elements. CO is made up of one carbon atom and one oxygen atom

5 0
3 years ago
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