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erik [133]
3 years ago
11

A glacier advanced down a mountain from an elevation of 2010 m to 1780 m in 5 years. What was the glaciers rate of change in a y

ear and a month?
the answer must also be shown in a graph
Physics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

The solution of the given problem is provided in the following subsection.

Explanation:

According to the question,

The change in the height of the glacier will be:

= 1780-2010

= -230

Change in time,

= 5 years

Now,

The rate of change will be:

= \frac{m}{years}           ∵ (1 year = 12 months)

= \frac{230}{5}

= -46 \ m/years

or,

The rate of change will be:

= \frac{m}{months}         ∵ (5 years in months = 5×12 months)

= \frac{-230}{5\times 12}

= \frac{-230}{60}

= =3.83 \ m/months

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