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3 years ago

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A glacier advanced down a mountain from an elevation of 2010 m to 1780 m in 5 years. What was the glaciers rate of change in a y

ear and a month?
the answer must also be shown in a graph

1 answer:

Ivanshal [37]3 years ago

6 0

Answer:

The solution of the given problem is provided in the following subsection.

Explanation:

According to the question,

The change in the height of the glacier will be:

= $1780-2010$

= $-230$

Change in time,

= 5 years

Now,

The rate of change will be:

= $\frac{m}{years}$ ∵ (1 year = 12 months)

= $\frac{230}{5}$

= $-46 \ m/years$

or,

The rate of change will be:

= $\frac{m}{months}$ ∵ (5 years in months = 5×12 months)

= $\frac{-230}{5\times 12}$

= $\frac{-230}{60}$

= $=3.83 \ m/months$

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3 years ago

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4 years ago

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san4es73 [151]

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3 years ago