The most pressing problem in the Chesapeake Bay is
2 answers:
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Answer:
K_{total} = 19.4 J
Explanation:
The total kinetic energy that is formed by the linear part and the rotational part is requested
let's look for each energy
linear
= ½ m v²
rotation
= ½ I w²
the moment of inertia of a solid sphere is
I = 2/5 m r²
we substitute
= ½ mv² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
K_{total} = ½ m w² r² + ½ (2/5 m r²) w²
K_{total} = m w² r² (½ + 1/5)
K_{total} = m w² r²
let's calculate
K_{total} = 6.40 16.0² 0.130²
K_{total} = 19.4 J
Answer:
<em>Angular displacement=68.25 rad</em>
Explanation:
<u>Circular Motion</u>
If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:
The angular displacement is given by:
The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:
Thus, the angular displacement is:
Angular displacement=68.25 rad