Answer:Zero
Explanation:
Given
mass of ball 
If the ball is thrown upward then at maximum point velocity of ball is zero because ball is no longer able to move upward
Momentum(P) of a particle is given by



Therefore at the highest point momentum is zero .
<span>Arsenic has a more nonmetallic behavior than antimony because arsenic's atoms have fewer electron shells.</span>
Answer:
(a). The distance is 49.79 m.
(b). The speed of the ball is 24.39 m/s.
Explanation:
Given that,
Speed = 20 m/s
Angle = 40°
Height = 22 m
Time = 3.25 sec
(a). We need to calculate the distance
Using formula of distance

Put the value into the formula


(b). We need to calculate the horizontal velocity
Using formula of velocity

Put the value into the formula


We need to calculate the vertical velocity
Using equation of motion

Put the value into the formula


Negative sign shows the opposite direction.
We need to calculate the speed of ball
Using formula of speed



Hence, (a). The distance is 49.79 m.
(b). The speed of the ball is 24.39 m/s.
Answer:
v = 0.059 m/s
Explanation:
To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:
(1)
m: mass of the ball = 0.400kg
M: mass of Olaf = 75.0 kg
v1i: initial velocity of the ball = 11.3m/s
v2i: initial velocity of Olaf = 0m/s
v: final velocity of Olaf and the ball
You solve the equation (1) for v and replace the values of all variables:

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s
Answer:
False
Explanation:
The formula of force that exists between two charges is expressed as;
F = kq1q2/r²
If two charges separated by one meter exert a 9 N force on each other, the;
9 = kq1q2/1²
9 = kq1q2 ..... 1
If the charges are pushed to a 3 meter separation, then;
F = kq1q2/3²
F = kq1q2/9 .... 2
Divide both equations;
9/F = (kq1q2)/ kq1q2/9
9/F = kq1q2 * 9/ kq1q2
9/F = 9
F = 9/9
F = 1N
Hence if the charges are pushed to a 3 meter separation, then the force on EACH charge will be 1N. Hence the answer is False