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sveticcg [70]
3 years ago
5

Solve -1/3a+5/6+2 1/6-5/6a

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

\frac{-1}{3}a + \frac{5}{6} +2\frac{1}{6} -\frac{5}{6}a\\\\\frac{-1}{3}a + \frac{5}{6} +\frac{13}{6} -\frac{5}{6}a\\\\\frac{-2a + 5 + 13-5a}{6}\\\\\frac{-7a +18}{6}

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You are studying the water properties of a bog in eastern Wisconsin and wish to estimate its acidity. You de ne a grid that cove
GenaCL600 [577]

Answer:

4.8-1.453\frac{1.3}{\sqrt{82}}=4.591    

4.8+1.453\frac{1.3}{\sqrt{82}}=5.009    

So on this case the 85% confidence interval would be given by (4.591;5.009)    

And we can conclude that the true mean for the acidity at 85% of confidence is between  (4.591;5.009)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=82-1=81

Since the Confidence is 0.85 or 85%, the value of \alpha=0.15 and \alpha/2 =0.075, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.075,81)".And we see that t_{\alpha/2}=1.453

Now we have everything in order to replace into formula (1):

4.8-1.453\frac{1.3}{\sqrt{82}}=4.591    

4.8+1.453\frac{1.3}{\sqrt{82}}=5.009    

So on this case the 85% confidence interval would be given by (4.591;5.009)    

And we can conclude that the true mean for the acidity at 85% of confidence is between  (4.591;5.009)    

6 0
4 years ago
Read 2 more answers
What is the answer to this problem 2/3+ 3/4<br> 5/6
svetlana [45]

Answer:

\frac{2}{3}  +  \frac{3}{4}  \\  \frac{8}{12}  +  \frac{9}{12}   \\ =  \frac{17}{12}  = 1\frac{5}{12}

6 0
4 years ago
Read 2 more answers
Will give brainliest answer!
kifflom [539]
5x + 60y = 35

x +y = 1.5 : rewrite as x = 1.5-y   and substitute this formula for x in the first one:

5(1.5-y) + 60y = 35

distribute:

7.5 - 5y + 60y = 35

combine like terms:

7.5 + 55y = 35

subtract 7.5 from both sides:

55y = 27.5

divide both sides by 55 to solve for  y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

x + 0.5 = 1.5

x = 1.5 - 0.5 = 1

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8 0
3 years ago
Explain how to determine if the two expressions are
antiseptic1488 [7]

Answer:

1. 120 o 88

Step-by-step explanation:

8(6)+40=88

8(10)+40=120

If you use any value to X the answers will be the same in both cases

4 0
3 years ago
Jackie kessel has found a home she would like to purchase. The seller accepts her offer of 210900. Jackie will make a down payme
raketka [301]
210900 × 0.15 = 31635
210900 - 31635 = 179265
179265 is the mortgage loan
3 0
3 years ago
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