For Ca(OH)2, Ksp = [Ca2+][OH-]^2
You have your Ksp as 6.5 x 10^-6. Your [OH-] comes almost entirely from the 0.10 mol of NaOH, since Ca(OH)2 barely dissolves. Your [OH-] is therefore 0.10 M (since you have 1 L of solution).
6.5 x 10^-6 = [Ca2+](0.10)^2
Solve for [Ca2+]:
6.5 x 10^-6 / (0.10)^2 = [Ca2+]
[Ca2+] = 0.00065 M
The maximum concentration of [Ca2+] is 0.00065 M, and you have 0.0010 M Ca(OH)2, so you’ll end up with 0.00065 M Ca2+ in solution.
Answer : Option D) Silicates.
Explanation : The minerals with the silicon-oxygen structures are classified as silicates.
As per the definition, A silicate is any member of a family which has anions consisting of silicon and oxygen, usually they have the general formula as [SiO].
It usually has a structure which has a central silicon ion which has a charge of (+4) while each oxygen has a charge of negative two (-2) and thus each silicon-oxygen bond is equal to one half (1/2) of the total bond energy of oxygen. Therefore, it confirms that the answer is Silicates.
Just 7 electrons this is the answer
Answer: 1) only a salt and water
An acid and base reacts together to undergo neutralization to form salt and water.
where HCl is an acid and NaOH is a base to form salt (NaCl) and water 
.
Answer: 2) The formula of the hydrogen ion is often written as 
.
All acids dissociate in water to give ions.
Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.
Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.
Answer: 4) A conjugate acid base pair transfers hydrogen ion.
Here 
accepts a proton and thus act as a base and the corresponding 
is its conjugate acid.
Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.
and 
is a acid which accepts proton and thus acts as base to form conjugate acid .
Answer:
Propenyl-benzene
Explanation:
Hello,
Elimination reaction of solid (1-chloropropyl)-benzene due to the heat in presence of ethanol turns out based on the attached picture in which both the chlorine a the hydrogen in the second carbon go out and subsequently get together to form propenyl-benzene and hydrochloric acid.
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