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4 years ago

When iron nail is ground into powder, it’s mass

Chemistry

1 answer:

Stolb23 [73]4 years ago

5 0

Answer:

(a) The mass of an object remains the same always. It is independent of its location. In this case, an iron nail is ground into powder.

Explanation:

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Electronic configuration of Ferrous sulphate

uranmaximum [27]

Answer:

It's no trouble

Explanation:

Electronic configuration of fe=1s2,2s2,2p6,3s2,3p6,4s2,3d6

e.c of fe3+=1s2,2s2, 2p6, 3s2, 3p6, 4s0, 3d5

e.c of S= 1s2,2s2, 2p6, 3s2, 3p4

e.c of s2-=1s2, 2s2, 2p6, 3s2, 3p6

Iron or Iron is the first element of the eighth group of the periodic table. This is the most attainable element in the womb and outside of the womb. This is the fourth most commonly found element in Earth's womb. It has four permanent isotopes, whose mass is 54, 56, 57 and 58.

[Ar] 3d6 4s2

5 0

3 years ago

If a satellite or spaceship explodes in outer space, you can see the explosion from a distance but you cannot hear it. Why?

labwork [276]

C) Sound is a mechanical wave and needs a medium to travel through while light is an electromagnetic wave.

There is no air for the sound waves to travel, therefore, no sound waves being transmitted.

3 0

3 years ago

Read 2 more answers

The solubility of lead(II) iodide is 0.064 g/100 mL at 20ºC. What is the solubility product for lead(II) iodide?

quester [9]

Answer:

$Ksp=1.07x10^{-8}$

Explanation:

Hello,

In this case, the dissociation reaction is:

$PbI_2(s)\rightleftharpoons Pb^{2+}(aq)+2I^-(aq)$

For which the equilibrium expression is:

$Ksp=[Pb^{2+}][I^-]^2$

Thus, since the saturated solution is 0.064g/100 mL at 20 °C we need to compute the molar solubility by using its molar mass (461.2 g/mol)

$Molar solubility=\frac{0.064g}{100mL}*\frac{1000mL}{1L}*\frac{1mol}{461.2g}=1.39x10^{-3}M$

In such a way, since the mole ratio between lead (II) iodide to lead (II) and iodide ions is 1:1 and 1:2 respectively, the concentration of each ion turns out:

$[Pb^{2+}]=1.39x10^{-3}M$

$[I^-]=1.39x10^{-3}M*2=2.78x10^{-3}M$

Thereby, the solubility product results:

$Ksp=(1.39x10^{-3}M)(2.78x10^{-3}M)^2\\\\Ksp=1.07x10^{-8}$

Regards.

6 0

4 years ago

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric

Luba_88 [7]

Complete Question

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.

Answer:

The pressure required is $P_2= 12.2 \ atm$