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-BARSIC- [3]
3 years ago
13

Re-write the quadratic function belbw in Standard Form y = 3(x - 3)(x - 2)

Mathematics
2 answers:
Harman [31]3 years ago
8 0

Answer:

y = 3x² - 15x + 18

Step-by-step explanation:

y = 3(x - 3)(x - 2) ← expand factors using FOIL

   = 3(x² - 5x + 6) ← distribute parenthesis by 3

y = 3x² - 15x + 18 ← in standard form

max2010maxim [7]3 years ago
3 0

ANSWER

<em>SEE</em><em> </em><em>EXPLANATION</em>

Step-by-step explanation:

3(x²-2x-3x+6)

3(x²-5x+6)

3x²-15x+18

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Solve for c: 2(4c-7) is greater than or equal to 8(c-3)
loris [4]

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3 years ago
What is the reciprocal for 2 2/5​
wariber [46]

Answer:

5/12

Step-by-step explanation:

2 2/5 = 12/5 so its reciprocal is 5/12

Reciprocals are fractions that are basically "flipped". You flip the denominator to the numerator and vice versa.

5 0
3 years ago
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F it costs $90 to feed a family of 3 for one week. (3 points)
Nataly [62]
Given:
$90 good for 3 pax for 1 week.

a) $90 / 3 = $30 cost to feed each person in a week
b) $30 cost to feed each person * 5 persons = $150
c) $30 cost to feed each person * 6 persons in a family = $180 

The formula derived from the above facts is:

Total cost = cost per person * no. of person * no. of weeks.

Assuming = 6 persons for 2 weeks
Total cost = 30 x 6 x 2
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8 0
3 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%
zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

p = 0.2*0.25 = 0.05

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

0.05 + 0.05*0.8 + 0.75*0.2 = 0.24

24% of the employees will suffer at least one lost-time accident over the two-year period

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