Answer:
x = 5/13
Step-by-step explanation:
![x+\dfrac{2}{13}=\dfrac{7}{13}\\\\ x+\dfrac{2}{13}-\dfrac{2}{13}=\dfrac{7}{13}-\dfrac{2}{13}\\\\x+0=\dfrac{7-2}{13}\\\\\boxed{x=\dfrac{5}{13}=0.38462}](https://tex.z-dn.net/?f=x%2B%5Cdfrac%7B2%7D%7B13%7D%3D%5Cdfrac%7B7%7D%7B13%7D%5C%5C%5C%5C%20x%2B%5Cdfrac%7B2%7D%7B13%7D-%5Cdfrac%7B2%7D%7B13%7D%3D%5Cdfrac%7B7%7D%7B13%7D-%5Cdfrac%7B2%7D%7B13%7D%5C%5C%5C%5Cx%2B0%3D%5Cdfrac%7B7-2%7D%7B13%7D%5C%5C%5C%5C%5Cboxed%7Bx%3D%5Cdfrac%7B5%7D%7B13%7D%3D0.38462%7D)
Answer:
Option D.
![A =96\pi\ cm^2](https://tex.z-dn.net/?f=A%20%3D96%5Cpi%5C%20cm%5E2)
Step-by-step explanation:
The area of the circular bases is:
![A_c = 2\pi(a) ^ 2](https://tex.z-dn.net/?f=A_c%20%3D%202%5Cpi%28a%29%20%5E%202)
Where
is the radius of the circle
Then
![A = 2\pi(4) ^ 2](https://tex.z-dn.net/?f=A%20%3D%202%5Cpi%284%29%20%5E%202)
![A = 32\pi\ cm^2](https://tex.z-dn.net/?f=A%20%3D%2032%5Cpi%5C%20cm%5E2)
The area of the rectangle is:
![A_r=b * 2\pi r](https://tex.z-dn.net/?f=A_r%3Db%20%2A%202%5Cpi%20r)
Where
![b=8\ cm](https://tex.z-dn.net/?f=b%3D8%5C%20cm)
b is the width of the rectangle and
is the length
Then the area of the rectangle is:
![A_r=8 * 2\pi (4)](https://tex.z-dn.net/?f=A_r%3D8%20%2A%202%5Cpi%20%284%29)
![A_r=64\pi\ cm^2](https://tex.z-dn.net/?f=A_r%3D64%5Cpi%5C%20cm%5E2)
Finally the total area is:
![A = A_c + A_r\\\\A = 32\pi\ cm^2 + 64\pi\ cm^2\\\\](https://tex.z-dn.net/?f=A%20%3D%20A_c%20%2B%20A_r%5C%5C%5C%5CA%20%3D%2032%5Cpi%5C%20cm%5E2%20%2B%2064%5Cpi%5C%20cm%5E2%5C%5C%5C%5C)
![A =96\pi\ cm^2](https://tex.z-dn.net/?f=A%20%3D96%5Cpi%5C%20cm%5E2)
Answer:
$2,589.52
Step-by-step explanation:
![A = P(1 + \dfrac{r}{n})^{nt}](https://tex.z-dn.net/?f=%20A%20%3D%20P%281%20%2B%20%5Cdfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D%20)
We start with the compound interest formula above, where
A = future value
P = principal amount invested
r = annual rate of interest written as a decimal
n = number of times interest is compound per year
t = number of years
For this problem, we have
P = 2000
r = 0.026
n = 2
t = 10,
and we find A.
![A = $2000(1 + \dfrac{0.026}{2})^{2 \times 10}](https://tex.z-dn.net/?f=%20A%20%3D%20%242000%281%20%2B%20%5Cdfrac%7B0.026%7D%7B2%7D%29%5E%7B2%20%5Ctimes%2010%7D%20)
![A = $2589.52](https://tex.z-dn.net/?f=%20A%20%3D%20%242589.52%20)
The least amount is the smallest amount, 1/8.