When it comes to reimbursement packages, company A offers $205 plus

1 answer:

6 0

220-205=15
So 15$ is the difference you need to make up .
.45times n +15 =.55times n

So I just times each answer to see
.45 times 325 is 146.25 miles plus 220= 366.25
.55times 325 is 178.75 miles plus 205= 383.75

.45 times 250 is 112.5 miles plus 220= 332.5
.55times 250 is 137.5 miles plus 205= 342.5

.45 times 225 is 101.25 miles plus 220= 321.25
.55times 225 is 123.75 miles plus 205= 328.75

.45 times 150 is 67.5 miles plus 220= 287.5
.55times 150 is 82.5 miles plus 205= 287.5

So it’s b 150 the last one I thought it could be....

Good luck brainliest would be appreciated

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Suppose we want to choose a value of x within 3 units of 11. [This means a value of x that is less than 3 units away from 11.] T

Dahasolnce [82]

Answer:

(a) [8, 14]

(b) $8 \leq x \leq 14$

(c)See attachment

Step-by-step explanation:

We want to choose a value of x within 3 units of 11.

(a)Now, 11-3=8 and 11+3=14

The possible values of x ranges is in the closed interval [8,14]

(b) Since x is within 3 units of 11., we have:

$|11-x|\leq3$

Solving the absolute inequality

$-3 \leq 11-x \leq 3\\$In $ -3 \leq 11-x\\ x \leq 11+3\\x \leq 14\\\\$In $ 11-x \leq 3\\ 11-3 \leq x\\8 \leq x\\$Therefore,an inequality that represents all values of x that meet this constraint is:$\\8 \leq x \leq 14$