Answer:
C-14 have 8 neutrons in the nucleus.
Carbon atoms with 8 neutrons have an atomic mass of 14 (6 protons + 8 neutrons = 14), so this isotope of carbon is named carbon-14.
hope it helps :)
Explanation:
Answer:
[NH₄NO₃] at D → 0.279 M
Explanation:
This exercise involves a series of dilutions one after the other.
First of all, we calcualte ammonium nitrate's concentration at A.
15.71 g . 1 mol/ 80 g = 0.196 mol / 0.150 mL = 1.31 M
At B → 1.31 M . 20 mL/ 75 mL = 0.349 M
At C → 0.349 M . 15 mL / 25 mL = 0.209 M
[NH₄NO₃] at B = 0.349 M
[NH₄NO₃] at C = 0.209 M
So let's calculate the new moles
In 1 mL of B we have 0.349 mmoles
In 10 mL of B we have 3.49 mmoles
In 1 mL of C we have 0.209 mmoles
In 10 mL of C we have 2.09 mmoles
Volume of D = 10 ml + 10ml = 20 mL
Total mmmoles = 3.49 mmoles + 2.09 mmoles = 5.58 mmoles
[NH₄NO₃] at D = 5.58 mmoles / 20mL → 0.279 M
Honestly idk if this is correct but. The noble-gas notation for lead (Pb) would be [Xe]6s^2 4f^14 5d^10 6p^2. The standard electron configuration of lead is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10 6p^2 simplifying will lead to the part having the same configuration as xenon to be written as [Xe].
Answer:
0.98 M
Explanation:
Given data:
Mass of sugar = 20 g
Mass of water = 59 g
Concentration of solution = ?
Solution:
1 g = 0.01 L
59 g× 0.01 L/1 g
0.059 L
Concentration formula:
C = m/v
m = moles of solute
v = volume of solution
Number of moles of sugar:
Number of moles = mass/molar mass
Number of moles = 20 g/ 342.3 g/mol
Number of moles = 0.058 mol
Now we will calculate the concentration:
C = 0.058 mol/0.059 L
C = 0.98 mol/L
C = 0.98 M