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hichkok12 [17]
3 years ago
7

Jackson will buy the items listed below. He has $422.76 in his checking account. He had a stored-valued card worth $75. He withd

rew cash to cover the remaining cost of the items. His bank automatically deducts a fee of $2.50 from the account for the withdrawal. After purchasing the items, how much money is left in Jackson's account?
Items. Cost($)

video game. 44.99

video game console. 299.49

a
$150.78
b
$269.48
c
$344.48
d
$497.76
Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

A

Step-by-step explanation:

44.99+299.49 = $344.38

$344.38 - store card ($75) = $269.48

422.76 - 269.48 - 2.5 = $150.78

Therefore answer is A

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Jack has twice as many dimes as quarters. If the total value of the coins is $6.30, how many dimes does he have?
ycow [4]

Answer:

Number of dimes = 28

Step-by-step explanation:

Given that:

Worth of coins = $6.30 = 6.30 * 100 = 630 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement;

x = 2y    Eqn 1

10x+25y = 630    Eqn 2

Putting x = 2y in Eqn 2

10(2y) + 25y = 630

20y + 25y = 630

45y = 630

Dividing both sides by 45

\frac{45y}{45}=\frac{630}{45}\\y=14

Putting y=14 in Eqn 1

x = 2(14)

x = 28

Hence,

Number of dimes = 28

4 0
3 years ago
Let f be defined by the function f(x) = 1/(x^2+9)
riadik2000 [5.3K]

(a)

\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}

(b) The series

\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}

converges by comparison to the convergent <em>p</em>-series,

\displaystyle\sum_{n=3}^\infty\frac1{n^2}

(c) The series

\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

converges absolutely, since

\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

5 0
3 years ago
What is the inverse one to one function of f(x) = square root of x-2???
alexira [117]
f(x) = \sqrt{x - 2} \\y = \sqrt{x - 2} \\y^{2} = (\sqrt{x - 2})^{2} \\y^{2} = x - 2 \\x^{2} = y - 2 \\x^{2} + 2 = y \\x^{2} + 2 = f^{-1}(x)
6 0
3 years ago
Determine which line is perpendicular to y = - 7/5x-2.​
tatuchka [14]

Answer:

y = 5/7 x  - 6

Step-by-step explanation:

For two lines to be perpendicular, the product of their slope must be -1

The slope of the given function is -7/5

Let the slope of the required function be m

m * -7/5 = -1

7/5 m = 1

7 = 5m

m = 5/7

The slope of the line perpendicular to the line is 5/7

The required equation (using any value of the y-intercept) is expressed as;

y = 5/7 x  - 6

Note that the y-intercept value was assumed and any value can be used

6 0
3 years ago
PLEASE HELP I WILL MARK BRANLIEST
Finger [1]

Answer:

SAS

Step-by-step explanation:

We must prove that triangles ABC and EDC are congruent.

Since BD bisects AE, then AC is congruent with CE.

Since AE bisects BD, then BC is congruent with CD

Angle C is 90° in the triangle EDC and is also 90° in triangle BCA because they are vertical angles.

Being two sides and the included angle congruent, then both triangles are similar by the SAS theorem.

Answer: SAS

4 0
2 years ago
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