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Lesechka [4]
3 years ago
9

The table shows a linear relationship between x and y.

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

Answer:

Step-by-step explanation:b

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If MNO IS NMO what statement best describes triangle MON?
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If <span>, what statement </span>best<span> describes triangle </span>MON<span>?</span>
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Find the distance between (3, −7) and (4, 1)
m_a_m_a [10]

Answer:sqrt65

Step-by-step explanation:

Distance formula d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

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Which statements can be used to describe a ray?
Wittaler [7]

Answer:

has only one endpoint

Step-by-step explanation:

think rays from the sun.

they start at the sun (a point) and go out in one direction for ever.

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3 years ago
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Which value cannot represent the probability of an event occurring? StartFraction 1 over 100 EndFraction 0. 29 85% Three-half.
Serjik [45]

Every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.

Given to us,

a.)  \dfrac{1}{100}

b.)  0.29

c.)  85%

d.)  \dfrac{3}{2}

The probability help us to know about the probability of specific events occurring.

For a sure event, the probability is always 1,

while for an event that will never happen the probability is always 0.

Thus, probability(p),  \bold{1 \geq p\geq 0}.

Now looking at the options,

a.)  \dfrac{1}{100} = 0.01

b.)  0.29

c.)  85% = 0.85

d.)  \dfrac{3}{2} = 1.5

Now comparing each option with \bold{1 \geq p\geq 0}.

Therefore, the only option which is not feasible is option d that is 1.5.

Hence, every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.

To know more visit:

brainly.com/question/795909

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2 years ago
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A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.
S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)

where:

(x_A,y_A)=(-7,3) are the coordinates of point A

(x_B,y_B)=(-1,0) are the coordinates of point B

(x_C,y_C) are the coordinates of point C

Solving the equation for x_C,

x_C = x_B + \frac{x_B-x_A}{3}=-1+\frac{-1-(-7)}{3}=1

Solving the equation for y_C,

y_C=y_B + \frac{y_B-y_A}{3}=0+\frac{0-3}{3}=-1

So, the coordinates of point C are

C(-1,1)

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4 0
3 years ago
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