A. BeCl2 sp2
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Answer:
ΔH = 125.94kJ
Explanation:
It is possible to make algebraic sum of reactions to obtain ΔH of reactions (Hess's law). In the problem:
1. 2W(s) + 3O2(g) → 2WO3(s) ΔH = -1685.4 kJ
2. 2H2(g) + O2(g) → 2H2O(g) ΔH = -477.84 kJ
-1/2 (1):
WO3(s) → W(s) + 3/2O2(g) ΔH = 842.7kJ
3/2 (2):
3H2(g) + 3/2O2(g) → 3H2O(g) ΔH = -716.76kJ
The sum of last both reactions:
WO3(s) + 3H2(g) → W(s) + 3H2O(g)
ΔH = 842.7kJ -716.76kJ
<h3>ΔH = 125.94kJ </h3>
The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
- We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂
Mass of Zn(C₂H₃O₂)₂ = 20.5 g
Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]
= 65 + 2[59]
= 183 g/mol
<h3>Mole of Zn(C₂H₃O₂)₂ =? </h3>
Mole = mass / molar mass
Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183
<h3>Mole of Zn(C₂H₃O₂)₂ = 0.112 mole </h3>
- Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:
Mole of Zn(C₂H₃O₂)₂ = 0.112 mole
Volume = 105 mL = 105 / 1000 = 0.105 L
<h3>Concentration of Zn(C₂H₃O₂)₂ =? </h3>
Concentration = mole / Volume
Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105
<h3>Concentration of Zn(C₂H₃O₂)₂ = 1.067 M</h3>
Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
Learn more: brainly.com/question/25511880
Answer:
The three compounds are different compounds
Explanation:
The mass of Nitrogen that combines with 1 gram of Oxygen in Compound A = 1.750 g
The mass of Nitrogen that combines with 1 gram of Oxygen in Compound B = 0.8750 g
The mass of Nitrogen that combines with 1 gram of Oxygen in Compound C = 0.4375 g
According to the law of multiple proportions, when atoms of two different elements react to form compounds, the masses of one of the elements that combines with a fixed mass of the other element are in small whole number ratios.
The ratio of the masses are;
Mass of Nitrogen in Compound B/(Mass of Nitrogen in Compound C = 0.8750/0.4375 = 2
Mass of Nitrogen in Compound A/(Mass of Nitrogen in Compound C = 1.750/0.4375= 4
Mass of Nitrogen in Compound A/(Mass of Nitrogen in Compound B = 1.750/0.8750= 2
Given that the masses of Nitrogen in the three compounds are in small whole number ratios, the three compounds, Compound A, Compound B, and Compound C are different compounds.
Answer:
I would say about 250 meters.
Explanation:
