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Ratling [72]
3 years ago
11

The volume of a gas is 5.0 L, when the temperature is 5.0 degrees Celsius. If the temperature is increased to 10.0 degrees Celsi

us with no change in pressure, what is the new volume?
Chemistry
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:5.1L

Explanation:

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The freezing point of benzene is 5.5°C. What is the freezing point of a solution of 2.60 g of naphthalene (C10H8) in 675 g of be
Mrac [35]

<u>Answer:</u> The freezing point of solution is 5.35°C

<u>Explanation:</u>

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point elevation constant = 4.90°C/m

m_{solute} = Given mass of solute (naphthalene) = 2.60 g

M_{solute} = Molar mass of solute (naphthalene) = 128.2 g/mol

W_{solvent} = Mass of solvent (benzene) = 675 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 4.90^oC/m\times \frac{2.60\times 1000}{128.2g/mol\times 675}\\\\\text{Freezing point of solution}=5.35^oC

Hence, the freezing point of solution is 5.35°C

3 0
3 years ago
Suppose a student did not fully redissolve the Al(OH)3 that initially formed upon the addition of H2SO4. Predict and explain how
kirza4 [7]
<span>Percent yield is the measured recovery of a substance in grams divided by the theoretical amount of substance expected in grams (times 100 to convert to %). Undissolved Aluminum trihydroxide would add mass to the Aluminum sulphate one is making here. The measured mass would be inaccurately high, increasing the percent yield calculated.</span>
6 0
3 years ago
How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?
Veseljchak [2.6K]

Are produced 72 grams of water in this reaction.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

                          Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

MM_{Ca(OH)_2} = 74.1g/mol

                                           MM = \frac{g}{mol}

                                             74.1 = \frac{35.8}{mol}\\mol = 2

So, if there are 2 mols of Ca(OH)2:

                                  Ca(OH)2    |    H2O

                                          \frac{1mol}{2mol} =\frac{2mol}{xmol}

                                             x = 4mol

Finally, just find the number of grams of water using your molar mass:

MM_{H_2O} = 18g/mol

                                              18= \frac{m}{4}\\m = 72g

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237

5 0
2 years ago
Plants get all their matter from soil. True or False
Elodia [21]

Answer:

False

Explanation:

Not all of it but some of it. Hope this helps! (ノ◕ヮ◕)ノ*:・゚✧

8 0
3 years ago
Write an equation for the neutralization of h2so4 by koh
Elena L [17]
Acid + alkali ------> salt + water
2KOH + H2SO4 ------> K2SO4 + 2H2O

Hope it helped!
3 0
3 years ago
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