Answer:
a) [ Ca2+ ] = 3.347 E-4 mol/L
b) [ Ca2+ ] = 1.5 E-8 mol/L
Explanation:
S S 2S......in the equilibrium
⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S )² = 4S³
⇒ S = ∛ ( 1.5 E-10 / 4 )
⇒ S = ∛ 3.75 E-11
⇒ S = 3.347 E-4 mol/L
⇒ [ Ca2+ ] = S = 3.347 E-4 mol/L
b) NaF ↔ Na+ + F-
0.10 M 0.10 0.10
S S 2S + 0.10
⇒ Ksp = 1.5 E-10 = [ Ca2+ ] * [ F- ]² = S * ( 2S + 0.10 )²
∴∴ the Concentration: 0.10 M >>>> Ksp ( 1.5 E-10 ), son we can despise S as adding.
⇒ 1.5 E-10 = S * ( 0.10 )² = 0.01 S
⇒ S = 1.5 E-10 / 0-01
⇒ S = 1.5 E-8 mol/L
⇒ [ Ca2+ ] = S = 1.5 E-8 mol/L
The answer would be A. troposphere
I’m pretty sure the velocity increases as the time of an object falling increases :)
B it is an aldose to ketose isomerization
