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3 years ago

10

I don't understand how to find the area of a circle

2 answers:

Liula [17]3 years ago

6 0

You have to find out the radius of the circle so u have to find it in the middle of the circle

Darina [25.2K]3 years ago

6 0

Area of a circle is calculated by this expression....

A = πR²

What this says is Area is equal to the radius squared times pi (3.14 for all intensive purposes.)

So, we need to find A (area.)

We know the diameter (d) is twice the radius, and we know that the diameter is 10.

10/2 = 5.

The radius is 5.

A = π5²

5² = 5 x 5 = 25

A = π25

3.14 (π) * 25 = 78.5

The area of the circle with the diameter of 10 is 78.5 roughly. This is not exact but for what you are doing it will suffice.

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AleksandrR [38]

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3 years ago

How many points need to be removed from this graph so it will be a function?

finlep [7]

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3 points

Step-by-step explanation:

in a function, an x-value must have only one y-value correlated with it.

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And, you would need to remove either (2, -2) or (2, -4)

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1 year ago

12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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3 years ago

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blsea [12.9K]

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2 years ago

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