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Pie
3 years ago
14

The breaking and forming of bonds between atoms in substances results in changes in the _______ contained in the substances.

Chemistry
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer:

Electrons

Explanation:

The breaking and forming of bonds between atoms in substances results in changes in the number of electrons in the substance.

  • Atoms combined in order to share, gain or lose electrons for it to be stable.
  • The noble gases have a set up configuration which makes them stable.
  • All atom tend to mimic the noble gases.
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O
viva [34]

Answer:

The second and third option are isotopes of Bromine

Z=  35 A = 79

A = 79  N= 44

Explanation:

Step 1: What are isotopes ?

⇒ Elements  with same atomic number (Z) ( this means the same number of electrons and protons) but a different number of neutrons (N)

The atomic number (visible on the periodic table) is the number of protons.

The atomic mass is  the sum of the protons (Z) and neutrons (N), and is showed as 'A'. So A = Z+N

If we look at the periodic table, we can see that the atomic number of bromine (Z) = 35. This means the amount of protons = 35. Since isotopes have the same amount of protons, all isotopes of bromine, have 35 protons.

1) Z = 79, A = 196

Z = protons = electrons .So this element has 79 protons, as well as 79 electrons.

196 = 79 + N ⇒ N = 196 - 79 = 117 neutrons

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Gold (Au): 196Au

2) Z = 35 , A = 79

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons.

79 =35 + N ⇒ N = 79 - 35= 44 neutrons

⇒Since it does have 35 protons, it is an isotope of Bromine. This isotope has 44 neutrons

⇒ This is 79Br, which is a stable isotope of Bromine.

3) A=79, N = 44

Z = A - N ⇒ Z = 79 - 44 = 35

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons. It also has 44 neutrons.

⇒Since it does have 35 protons, it is an isotope of Bromine, with 44 neutrons: 79Br

4) Z = 44, N = 44

Z = protons = electrons .So this element has 44 protons, as well as 44 electrons.

A = 44 + 44 ⇒ A = 88  

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Ruthenium (Ru) : 88Ru

⇔So the <u>second</u> and<u> third</u> option are isotopes of Bromine

6 0
3 years ago
In which direction does the reaction proceed after heating to 2000 °c?
e-lub [12.9K]
What do I possibly answer here?
ask a full question pls!
6 0
3 years ago
A laboratory assistant needs to prepare 35.2 liters of hydrogen at 25.0°C and 101.3 kilopascals. This is the equation for the re
lisabon 2012 [21]

Volume of hydrogen gas = 35.2L

Temperature of hydrogen gas = 25.0°C + 273 = 298 K

Pressure of hydrogen gas = 101.3 kPa = 1 atm

(Conversion factor 1 atm = 101.325 kPa)

Using the Ideal gas law,

PV = nRT

where P, V, n, R and T are pressure, volume, number of moles, universal gas constant and temperature respectively.

n = PV/RT

The number of moles of hydrogen gas,

n = 35.2 L x 1 atm/ 0.0821 L.atm.mol⁻¹1.K⁻¹ x 298 K

n = 1.438 moles


2HCl + Ca → H₂ + CaCl₂

Based on the given balanced equation, 1 mole of H₂ is produced from two  moles of HCl.

Since H₂ is 1.438 moles, HCl will be (1.438 x 2) moles or 2.876 moles

Given, Molarity of HCl = 2.3 M

Molarity = moles of solute / liter of the solution

Thus the volume of HCl is,

2.3 M = 2.876 moles / liter of the solution

V = 2.876 moles / 2.3 M

V = 1.25 L

Thus the volume of 2.3 M hydrochloric acid required to produce the given amount gas is 1.25 L.

6 0
3 years ago
Read 2 more answers
What’s the answer???????#15
Lady_Fox [76]

Answer:

C.They are only magnetic if an electric current is running through them

Explanation:

Electromagnets are conductors which develop a magnetic field due to the electrons flowing through them. If the flow of electric current stops, the motion of the electrons stop and they do not generate their magnetic fields.

7 0
2 years ago
Calculate the pH of a buffer prepared by mixing 20.0 mL of 0.10 M acetic acid and 55.0 mL of 0.10 M sodium acetate
MatroZZZ [7]

Answer:

Calculate the pH of a buffer prepared by mixing 30.0 mL of 0.10 M acetic acid and 40.0 mL of 0.10 M sodium acetate.

3 0
4 years ago
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