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Novosadov [1.4K]
3 years ago
5

In 1954, after he had helped develop the atomic bomb, j. robert oppenheimer was investigated and denied future access to classif

ied information because _____.
Chemistry
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

He had communist friends and family.

Explanation:

Hello,

In this case, it is widely known that Robert Oppenheimer (1904-1967) was a scientist who was part of the Manhattan Project formed to create the atomic bomb. At the Los Alamos laboratory he performed his scientific work in the light of researching and designing the bomb, that is why he is the soc-called father of such bomb. By 1954, the lifeguards he had were removed, he started being investigated as well as his future access to the classified information was revoked since it was dug up he had friends and family supporting and living based on the communism.  

Best regards.

pav-90 [236]3 years ago
4 0
Julius Robert Oppenheimer was an American hypothetical physicist and teacher of material science at the University of California, Berkeley. He was examined and denied future access to grouped data since he had loved ones who had a place with the Communist Party.
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Why?

In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

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Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

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We have that the molecular mass of the substance will be:

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Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:

mol_{(NH_{4})2CO_{3}=\frac{mass_{(NH_{4})2CO_{3}}}{molarmass_{(NH_{4})2CO_{3}}}

mol_{(NH_{4})2CO_{3}=\frac{16.1g}{95.98\frac{g}{mol}}=0.167mol

Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:

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M=\frac{moles_{solute}}{volume_{solution}}\\\\volume_{solution}=\frac{moles_{solute}}{M}

Now, substituting and calculating, we have:

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Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.

Have a nice day!

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