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Furkat [3]
3 years ago
9

What happens when an element is oxidised?

Chemistry
2 answers:
eduard3 years ago
7 0

Answer:

The process in which a substance loses an electron in a chemical reaction is called oxidation. The atoms that lost electrons are said to be oxidized. Atoms can be oxidized by nonmetals. Reduction is gain of electrons and thus gaining of negative charge.

Explanation:

:)

SpyIntel [72]3 years ago
5 0
Gains negative charge
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Please help!!!!!!!!!!!!!!!!!!!
zimovet [89]

Answer:

Your body cells use the oxygen you breathe to get energy from the food you eat. This process is called cellular respiration. During cellular respiration the cell uses oxygen to break down sugar. Breaking down sugar produces the energy your body needs.

Explanation:

Brainly pls

3 0
2 years ago
Gaseous methane CH4 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the t
Murrr4er [49]

Answer:

50.8 g

Explanation:

Equation of reaction.

CH_4 + 2O_2 \to CO_2 + 2H_2O

From the given information, the number of moles of methane = mass/ molar mass

= 15.4 g /  16.04 g/mol

= 0.960 mol

number of moles of oxygen gas = 90.3 g / 32 g/ mol

= 2.82 mol

Since 1 mol of methane requires 2 moles of oxygen

Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas

Thus, methane serves as a limiting reagent.

2.82 mol oxygen gas will result in 2.82 moles of water

So, the theoretical yield of water = moles × molar mass

= 2.82 mol × 18.01528 g/mol

= 50.8 g

8 0
3 years ago
Use your calculator to determine the answer to the following calculation:<br> 1.0×10^−15/4.2×10^−7
lianna [129]
1.0×10^−15/4.2×10^−7=<span>2.3809524e-23 Hoped I helped!</span>
8 0
3 years ago
What is the maximum amount of HCl, in grams, that can be produced if 37.5 g of BCl3 and 60.0 g of H2O are reacted according to t
Rus_ich [418]
Ooooh boy alright. So, this may or may not be a limited reactant problem so we need to first find out of it is.

First, how many moles of each substance are there

the molar mass of BCl3 is <span>117.17 grams so 37.5 g / 117.17 is ~ .32 mol.
The molar mass of H2O is 18.02 so 60 / 18.02 is ~ 3.33 mol.

Now, for every 1 mole of BCl3, there are 3 moles of HCl created. Therefore, BCl3 can create ~ .96 moles.
For every 3 moles of H2O, there are 3 moles of HCl created. Therefore, HCl can create ~3.33 moles.

But, there is not enough BCl3 to support that 3.33 moles, only enough for .96 moles, therefore BCl3 is the limiting reactant. Now, to answer the question, simply multiply .96 moles by the molar mass of HCl.

.96 x 36.46 = ~35 g</span>
6 0
3 years ago
I need help with #2 and #4 please
Arte-miy333 [17]
For #4 is 298.48 hope it is correct
4 0
3 years ago
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