Answer:
Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
i need points thanks for CO2moles
Answer: Option (a) is the correct answer.
Explanation:
A chemical formula which represents proportions between the elements present in a compound is known as empirical formula.
When chemical or molecular formula is able to be reduced to smaller whole-number ratio of the elements then both molecular and empirical formulas are considered to be the same.
Relation between molecular formula and empirical formula is as follows.
Molecular formula = n × Empirical formula
where, n is an integer.
Chemical formula of acetic acid is
.
Chemical formula of formaldehyde is
. It is the smaller whole-number ratio of molecular formula of acetic acid.
Chemical formula of Benzaldehyde is
.
Chemical formula of glucose is
.
Thus, we can conclude that formaldehyde molecules has/have the same empirical formula as acetic acid (
).
Answer:

Explanation:
Hello,
In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:
![pH=pKa+log(\frac{[base]}{[acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29)
Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:
![pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1](https://tex.z-dn.net/?f=pH%3D-log%28Ka%29%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29%5C%5C%5C%5CpH%3D-log%286.3x10%5E%7B-5%7D%29%2Blog%28%5Cfrac%7B0.33M%7D%7B0.42M%7D%20%29%5C%5C%5C%5CpH%3D4.1)
Regards.
Answer: Combustion is also known as burning, and the substance that burns is usually referred to fuel. The products of a complete combustion reaction include carbon dioxide (CO2) and water vapor (H2O).
Explanation:
Answer is 123
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