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bogdanovich [222]
3 years ago
9

How do you find the molar mass of a hydrate

Chemistry
1 answer:
Darya [45]3 years ago
6 0

If you mean hydrate as in <em>MgSO4 · 7H2O, </em>then simply find the molar mass of each element you see.

For the example above, that means you would add the molar mass (found on the periodic table) of Mg, then S, then 4(O), 14(H), and 7(O).

The results would be your molar mass for the hydrate.

I hope this is what you meant by your question!

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Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat of vaporization is 540 cal/g . A canister is
Pani-rosa [81]
<span>294400 cal The heating of the water will have 3 phases 1. Melting of the ice, the temperature will remain constant at 0 degrees C 2. Heating of water to boiling, the temperature will rise 3. Boiling of water, temperature will remain constant at 100 degrees C So, let's see how many cal are needed for each phase. We start with 320 g of ice and 100 g of liquid, both at 0 degrees C. We can ignore the liquid and focus on the ice only. To convert from the solid to the liquid, we need to add the heat of fusion for each gram. So multiply the amount of ice we have by the heat of fusion. 80 cal/g * 320 g = 25600 cal Now we have 320 g of ice that's been melted into water and the 100 g of water we started with, resulting in 320 + 100 = 420 g of water at 0 degrees C. We need to heat that water to 100 degrees C 420 * 100 = 42000 cal Finally, we have 420 g of water at the boiling point. We now need to pump in an additional 540 cal/g to boil it all away. 420 g * 540 cal/g = 226800 cal So the total number of cal used is 25600 cal + 42000 cal + 226800 cal = 294400 cal</span>
6 0
3 years ago
When you add water to calcium oxide it makes calcium hydroxide
Romashka [77]
Yes you add water to calcium oxide it makes calcium hydroxide
7 0
3 years ago
8. What is the heat of reaction when hydrogen and oxygen combine to form water?
valina [46]

Answer:

The heat of reaction when hydrogen and oxygen combine to form water is :

<u>C. 571.6 kJ</u>

Explanation:

Enthalpy Change = The enthalpy change for the formation of 1 mole of the substance from their standard state is called the enthalpy of formation.

This is intensive quantity as it is fixed for 1 mole .

Intensive properties = Those properties which are independent on the amount of the substance are intensive properties.

The value of these quantities does not get halve if you divide the substance into two equal parts. example , density, refractive index.

However , the enthalpy of reaction is extensive. Because on increasing the amount the value of the enthalpy also get doubles

Hence for this reaction :

2H_{2}(g)+O_{2}\rightarrow 2H_{2}(l)

Its value is -285.8 kJ for 1 mole

And here two moles are present . so the value of molar enthalpy is:

-285.8 x 2 = -571.6 kJ

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4 years ago
The standard unit for concentration, Molarity (M) can also be written as?
emmasim [6.3K]

mole is the standardized form of molarity

8 0
3 years ago
Is water a element or compond <br> and is it a homogeneous or heterogeneous
crimeas [40]

Answer:

Water is a compound. It contains more than one element

water is homogeneous

8 0
3 years ago
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