Ions stick together with<br> A . Covalent bonds <br> B. Negative bonds<br> C. Ionic bonds

The rate constant for the first-order decomposition at 45 °C of dinitrogen pentoxide, N2O5, dissolved in chloroform, CHCl3, is 6

weeeeeb [17]

Answer:

Rate of the reaction= 9.92× 10^-5 M² min-1

Explanation:

Using the equation of reaction

2N2O5 ⟶ 4NO2+O2

Rate = k[N2O5]²

From the question k= 6.2×10-4

[N2O5]= 0.4

Rate = 6.2×10-4[0.4]²= 9.92×10-5M² min-1

7 0

3 years ago

Which material property is most directly related to the x-axis value at the x-intercept of the interatomic force versus distance

Brrunno [24]

Answer:

Explanation:

The mechanical properties of a material affect how it behaves as it is loaded. The elastic modulus of the material affects how much it deflects under a load, and the strength of the material determines the stresses that it can withstand before it fails

3 0

2 years ago

Acetanilide has a solubility of 1.00 g/185 ml in 25 oc water and 1.00 g/20 ml in 100 oc water. what is the minimum volume of wat

Likurg_2 [28]

In the crystallization process the solid compound is dissolved in the solvent at elevated temperature and the crystallize product obtained by slow cooling of the solution. Here the solubility of acetanilide at 100°C is 1g per 20mL of water. Thus to dissolve 500mg of acetanilide at high temperature that is 100°C we need 10mL of water.

Now at 25°C after the re-crystallization there will be some amount of dissolve acetanilide. Which can be calculated as- 185mL of water is needed to dissolve 1g or 1000mg of acetanilide at 25°C. Thus in 10mL of water there will be $\frac{10X1000}{185}=54.05$ gmg of acetanilide.

6 0

3 years ago

An archaeologist discovered some charcoal at an excavation site. He sent the samples to a lab for C-14 dating, knowing that the

klio [65]

Here we assume that disintegration has occur so the normal t½ formular will not be used
mathematically we..⅛×5600 =700
therefore it is about 700years option A

7 0

3 years ago

P4O10(s) = -3110 kJ/mol H2O(l) = -286 kJ/mol H3PO4(s) = -1279 kJ/mol Calculate the change in enthalpy for the following process:

mash [69]

Answer:

-290KJ/mol

Explanation:

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}

ΔHrxn = 4(-1279) - [6(-286) - 3110]

= -5116 -(-1716-3110)

= -5116-(-4826)

= -5116 + 4826 = -290KJ/mol

6 0

3 years ago

Ions stick together with A . Covalent bonds B. Negative bonds C. Ionic bonds