2Cu(NO3)2 ----------> 2CuO (s) +4NO2 (g) + O2(g)
9.378g=0.05moles
no of moles = weight / MW = 9.378/187.56 = 0.05moles
as per the above reaaction 2moles of Cu(NO3)2 can produce 4moles of N2
0.05moles Cu(NO3)2 can produce (0.05*4)/2 = 0.1moles of N2
and 2moles of Cu(NO3)2 can produce 1moles of O2
0.05moles Cu(NO3)2 can produce (0.05*1)/2 = 0.025moles of O2
Total moles of gas i.e., N2 and O2 =0.1+0.025 = 0.125moles
From PV = nRT
V = nRT/ P = 0.125*0.0821*273 = 2.80166Lit option is correct
<u>Answer:</u> The molarity of 
ions in the solution is 0.306 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute 
= 15.6 g
Molar mass of = 295.6 g/mol
Volume of solution = 345 mL
Putting values in above equation, we get:
As, 1 mole of produces 1 mole of copper (II) ions and 2 moles of nitrate ions.
So, molarity of ions = (2 × 0.153) = 0.306 M
Hence, the molarity of ions in the solution is 0.306 M
Answer:
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Explanation:
Reaction rate, in chemistry, the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time. Alternatively, it may be defined in terms of the amounts of the reactants consumed or products formed in a unit of time. For example, suppose that the balanced chemical equation for a reaction is of the form
A + 3B → 2Z.
Answer:
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