Step-by-step explanation:
The simplest method is "brute force". Calculate each term and add them up.
∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)
∑ = 3 + 6 + 9 + 12 + 15
∑ = 45
∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²
∑ = 4 + 16 + 36 + 64
∑ = 120
∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)
∑ = -4 + -2 + 0 + 2
∑ = -4
4. 1 + 1/4 + 1/16 + 1/64 + 1/256
This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:
a = 1 (1/4)ⁿ⁻¹
So the series is:
5. -5 + -1 + 3 + 7 + 11
This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:
a = -5 + 4(n−1)
a = -5 + 4n − 4
a = 4n − 9
So the series is:
The answer is 3x10^12 also can i get brainliest please??
Answer:
Once upon a time, there were a two person family who lived out in the woods. The father took great care of the son. The father was a Botany, but had retired because of his age. But still he loved plants and grew a garden. The garden included Giant Bird of Paradise, Carnations, Irises, and ofc roses. He loved plants so much that he went out to dig a hole and plant different flowers and plants every spring. When the son grew older he helped the father with the garden. Two years later his son was accused of murder, but the body wasn't found. Next spring came and the father went out to dig. He couldn't Finnish it. He called his son and say he couldn't do the garden thing, because of his age. The son said don't dig there that's where he hid the bodies. The police came to dig the holes and try to find the bodies, but none of them were found. The father called the son again, and the son said thats all I can do for you right now.
Step-by-step explanation:
Answer: the second
one
Step-by-step explanation:
The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
