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nadya68 [22]
4 years ago
10

i have a simple question if i have (f + g)(x) = 2x + 7 + 6x – 5 and i combine 2x and 6x is it 8x or 8x^2?

Mathematics
2 answers:
dybincka [34]4 years ago
5 0
It is 8x because you're adding them not multiplying them. If you were multiplying it would be8x^2

Alexeev081 [22]4 years ago
4 0
<span>(f + g)(x) = 2x + 7 + 6x – 5 

// 2x + 6x = 8x
// 7 - 5 = 2

Therefore,
</span>(f + g)(x) = 8x + 2
<span>
Answer: 8x + 2

</span>
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Which point lies on a circle that is centered at A(-3, 2) and passes through B(1, 3)?
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\hbox{the center: } A(-3,2) \\&#10;h=-3 \\ k=2 \\ \\&#10;\hbox{the equation:} \\&#10;(x+3)^2+(y-2)^2=r^2 \\ \\&#10;\hbox{the circle passes through B(1,3)} \\&#10;x=1 \\ y=3 \\ \Downarrow \\&#10;(1+3)^2+(3-2)^2=r^2 \\&#10;4^2+1^2=r^2 \\&#10;16+1=r^2 \\&#10;17=r^2 \\ \\&#10;\hbox{the equation is:} \\&#10;(x+3)^2+(y-2)^2=17

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C(-1,-2) \\&#10;(-1+3)^2+(-2-2)^2=17 \\&#10;2^2+(-4)^2=17 \\&#10;4+16=17 \\&#10;20=17 \\&#10;not \ true \\ \\&#10;D(-6,3) \\&#10;(-6+3)^2+(3-2)^2=17 \\&#10;(-3)^2+1^2=17 \\&#10;9+1=17 \\&#10;10=17 \\&#10;not \ true

E(-3,-3) \\&#10;(-3+3)^2+(-3-2)^2=17 \\&#10;0^2+(-5)^2=17 \\&#10;25=17 \\&#10;not \ true \\ \\&#10;F(-2,6) \\&#10;(-2+3)^2+(6-2)^2=17 \\&#10;1^2+4^2=17 \\&#10;1+16=17 \\&#10;17=17 \\&#10;true

The answer is F(-2,6).
8 0
3 years ago
What is the image of (-4,-2) after a reflection over the line y = -x?
polet [3.4K]

Answer:

(2, 4).

Step-by-step explanation:

For y = -x  the transform is:

( x, y )  reflects to (-y, - x)

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4 0
2 years ago
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The correct answer for this very hard equation would happen to be 12 because 18+12 happens to equal 30 and 42-30 just so happens to equal 12
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3 years ago
Read 2 more answers
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