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3 years ago

Find the volume of the prism shown.

Mathematics

1 answer:

Sever21 [200]3 years ago

7 0

Answer:

41.16 m³

Step-by-step explanation:

Volume = area triangle x height

1/2(2.8x4.2) = 1/2( 11.76) = 5.88

5.88 x 7 = 41.16

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You have prices to rev

Alex17521 [72]

Answer:

34 minutes

Step-by-step explanation:

Given

$Time\ Spent = 6$

$Phone\ Calls = 40$

Required

Number of minutes left to spend (x)

Since there's only 1 minute left to spend on every other call;

Time left = x * 1

Time left = x

The required can further be calculated using:

$Time\ Spent + Time\ Left = Phone\ Calls$

This gives:

$6 + x = 40$

Subtract 6 from both sides

$x = 40 - 6$

$x = 34$

<em>Hence, there are 34 minutes left to spend</em>

8 0

3 years ago

What is the maximum value of the objective function, P, with the given constraints?

maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

$P=20x+35y$

Constraints,

$x+y \leq 12$

$5x+y \leq 20\\x \geq 0\\y \geq 0$

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

$P=20x+35y$

Point (0,0)

$P=20(0)+35(0)=0$

$P=20x+35y$

Point (0,12)

$P=20(0)+35(12)=420$

Point (2,10)

$P=20(2)+35(10)=40+350=390$

Point (4,0)

$P=20(4)+35(0)=80$

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0

3 years ago

If a wheel with a radius of 80 inches spins at a rate of 50 revolutions per minute, find the approximate linear velocity in mile

Lubov Fominskaja [6]

$\bf \textit{arc's length}\\\\
s=rw\qquad 
\begin{cases}
r=radius\\
w=\textit{angular speed}
\end{cases}\qquad w=\cfrac{50 rev}{min}\cdot \cfrac{2\pi }{rev}
\\\\\\
w=\cfrac{100\pi }{min}\qquad s=80in\cdot \cfrac{100\pi }{min}\implies s=\cfrac{8000\pi\ in}{min}\\\\
-------------------------------\\\\
\textit{now to convert it to miles/hr}
\\\\\\
\cfrac{8000\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mile}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{8000\pi \cdot 60\ in}{12\cdot 5280\ hr}$