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jarptica [38.1K]
3 years ago
15

A student submerges an irregularly object in a graduated cylinder half filled with water. The level of the water in the cylinder

rises from 17.8 ml to 49.7 ml. If the density of water is 0.9984 kg/liter, calculate the mass of the object in grams. The use of correct number of significant figures is required in answering all questions.
Physics
1 answer:
lakkis [162]3 years ago
7 0

solution:

volume of cylinder = change in level of water

volume of cylineder=(49.7-17.8)mL

=31.9mL

=0.0319liter

Mass= density x volume

=09984 x 0.0319

=0.0318kg

=31.8gm


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a motorcycle starts from rest covers 200 meter distance in 6 second calculate final velocity and acceleration​
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Explanation:

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Tudy the images about geologic time.
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A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

m is the satellite's mass

v is the speed

R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

M is the mass of the asteroid

Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

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R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula,

v=\sqrt{\frac{(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=8.11 m/s

B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

v=\sqrt{\frac{2GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=11.47 m/s

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3 years ago
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