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jarptica [38.1K]
3 years ago
15

A student submerges an irregularly object in a graduated cylinder half filled with water. The level of the water in the cylinder

rises from 17.8 ml to 49.7 ml. If the density of water is 0.9984 kg/liter, calculate the mass of the object in grams. The use of correct number of significant figures is required in answering all questions.
Physics
1 answer:
lakkis [162]3 years ago
7 0

solution:

volume of cylinder = change in level of water

volume of cylineder=(49.7-17.8)mL

=31.9mL

=0.0319liter

Mass= density x volume

=09984 x 0.0319

=0.0318kg

=31.8gm


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<span>f(x) = 5.05*sin(x*pi/12) + 5.15

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   The final thing that might have been needed would have been a phase correction. With this problem, we don't need a phase correction since at X = 0 (midnight), the value of X*pi/12 = 0, and the sine of 0 is 0, so the value of the equation is 5.15 which matches the given value of 5.15. But if the problem had been slightly different and the height of the tide at midnight has been something like 7 feet, then we would have had to calculate a phase shift value for the function and add that constant to the parameter being passed into sine, making the function look like:
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