Answer:
The net emissions rate of sulfur is 1861 lb/hr
Explanation:
Given that:
The power or the power plant = 750 MWe
Since the power plant with a thermal efficiency of 42% (i.e. 0.42) burns 9000 Btu/lb coal, Then the energy released per one lb of the coal can be computed as:
= 3988126.8 J
= 3.99 MJ
Also, The mass of the burned coal per sec can be calculated by dividing the molecular weight of the power plant by the energy released per one lb.
i.e.
The mass of the coal that is burned per sec
The mass of the coal that is burned per sec = 187.97 lb/s
The mass of sulfur burned
= 2.067 lb/s
To hour; we have:
= 7444 lb/hr
However, If a scrubber with 75% removal efficiency is utilized,
Then; the net emissions rate of sulfur is (1 - 0.75) × 7444 lb/hr
= 0.25 × 7444 lb/hr
= 1861 lb/hr
Hence, the net emissions rate of sulfur is 1861 lb/hr
Answer:
nreaker
Explanation:
A switch that automatically interrupts or shuts off an electric current at the first indication of a overload
Answer:
11 ounces
Explanation:
The patient gets 11 ounces of liquid.
From the description of this problem:
Xavier administers four cups of liquid each containing two ounces
The number of ounces in the four cups = 2 x 4 = 8ounces
Also,
One cup of the liquid contains 3 ounces.
Total number of ounces administered = 8 + 3 = 11 ounces.
Answer:
The gravitational force becomes 4 times i.e 400N
Explanation:
The acceleration on surface of moon =1.67m/s^2
Weight =mass ×acceleration
=7×1.67
=11.69N