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snow_lady [41]
3 years ago
9

The total charge a battery can supply is rated in mA⋅h , the product of the current (in mA ) and the time (in h ) that the batte

ry can provide this current. A battery rated at 1000 mA⋅hr can supply a current of 1000 mA for 1.0 h , 500 mA current for 2.0 h , and so on. A typical AA rechargeable battery has a voltage of 1.2 V and a rating of 1800 mA⋅h . Part A For how long could this battery drive current through a long, thin wire of resistance 34 Ω ? Express your answer in hours. Δt Δ t = nothing h SubmitRequest Answer Provide Feedback Next
Physics
1 answer:
natita [175]3 years ago
4 0

Answer: 0.2  hours

Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA  in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .

Besides, this battery has a voltage of 12 V

so by using the Ohm law we also know that V=R*I,

Fron this we can obtain:

I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA

then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA  in x time in the form:

1hour------- 1800 mA

x hour--------350 mA

time= 350/1800= 0.2 hour

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The whole question is talking about the amplitude of a wave
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Equilibrium to the crest . . . that's the amplitude.

Crest to trough . . . that's double the amplitude.

Trough to trough . . . How did that get in here ?  Yes, that's
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6 0
3 years ago
Observations must be _____. <br> subjective <br> objective <br> biased <br> deductive
Dmitrij [34]
Objective
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6 0
3 years ago
Read 2 more answers
If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth
fgiga [73]

<u>Answer:</u> The elevation in boiling point is 1.024°C.

<u>Explanation:</u>

To calculate the elevation in boiling point, we use the equation:

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Putting values in above equation, we get:

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3 years ago
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Answer:

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3 years ago
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