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iVinArrow [24]
3 years ago
11

A nail in a pine board stops a 4.9-N hammer head from an initial downward velocity of 3.2 m/s in a distance of 0.45 cm. In addit

ion, the person using the hammer exerts a 15-N downward force on it. Assume that the acceleration of the hammer head is constant while it is in contact with the nail and moving downward.
(a) Draw a free-body diagram for the hammer head. Identify the reaction force for each action force in the diagram.
(b) Calculate the down-ward force F exerted by the hammer head on the nail while the hammer head is in contact with the nail and moving downward.
(c) Suppose that the nail is in hardwood and the distance the hammer head travels in coming to rest is only 0.12 cm. The downward forces on the hammer head are the same as in part
(d). What then is the force F exerted by the hammer head on the nail while the hammer head is in contact with the nail and moving downward?

Physics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

Explanation:see attachment for answers and calculations

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3 0
3 years ago
a car accelerates along a straight road from rest to 75km/h in 5.0s. What is the magnitude of its average acceleration? show up
kykrilka [37]

Answer:

4.186 m/s^2

Explanation:

First, convert km/hr to m/s:

(75 km/hr)(1000m/1km)(1hr/60min)(1min/60s) = 20.83 m/s

Then, divide 20.93 m/s by 5.0s

(20.93 m/s) / (5.0s) = 4.186 m/s^2

5 0
2 years ago
The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top
leva [86]

Answer:

44.1613858478 m/s

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement = 99.4

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 99.4+0^2}\\\Rightarrow v=44.1613858478\ m/s

If air resistance was absent Dan Koko would strike the airbag at 44.1613858478 m/s

6 0
2 years ago
A 4.3 kg steel ball and 6.5 m cord of negligible mass make up a simple pendulum that can pivot without friction about the point
Alekssandra [29.7K]

Answer

given,

mass of steel ball, M = 4.3 kg

length of the chord, L = 6.5 m

mass of the block, m = 4.3 Kg

coefficient of friction, μ = 0.9

acceleration due to gravity, g = 9.81 m/s²

here the potential energy of the bob is converted into kinetic energy

m g L = \dfrac{1}{2} mv^2

v= \sqrt{2gL}

v= \sqrt{2\times 9.8\times 6.5}

      v = 11.29 m/s

As the collision is elastic the velocity of the block is same as that of bob.

now,

work done by the friction force = kinetic energy of the block

f . d = \dfrac{1}{2} mv^2

\mu m g. d = \dfrac{1}{2} mv^2

d=\dfrac{v^2}{2\mu g}

d=\dfrac{11.29^2}{2\times 0.9 \times 9.8}

    d = 7.23 m

the distance traveled by the block will be equal to 7.23 m.

8 0
3 years ago
3. How long will it take a ball to reach the ground if it falls from a cliff 25 m tall (starting from rest)? What if the ball we
Nady [450]

Answer:

2.26 s

Explanation:

Let's take down to be positive.

Given (in the y direction):

Δy = 25 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

25 m = (0 m/s) t + ½ (9.8 m/s²) t²

25 = 4.9t²

t = 2.26 s

If the ball instead had an initial horizontal velocity of 5 m/s, its initial vertical velocity is still 0 m/s.  So the time to fall is still 2.26 s.

4 0
3 years ago
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