A nail in a pine board stops a 4.9-N hammer head from an initial downward velocity of 3.2 m/s in a distance of 0.45 cm. In addit
ion, the person using the hammer exerts a 15-N downward force on it. Assume that the acceleration of the hammer head is constant while it is in contact with the nail and moving downward.
(a) Draw a free-body diagram for the hammer head. Identify the reaction force for each action force in the diagram.
(b) Calculate the down-ward force F exerted by the hammer head on the nail while the hammer head is in contact with the nail and moving downward.
(c) Suppose that the nail is in hardwood and the distance the hammer head travels in coming to rest is only 0.12 cm. The downward forces on the hammer head are the same as in part
(d). What then is the force F exerted by the hammer head on the nail while the hammer head is in contact with the nail and moving downward?
(a) Draw a free-body diagram for the hammer head. Identify the reaction force for each action force in the diagram.
(b) Calculate the down-ward force F exerted by the hammer head on the nail while the hammer head is in contact with the nail and moving downward.
(c) Suppose that the nail is in hardwood and the distance the hammer head travels in coming to rest is only 0.12 cm. The downward forces on the hammer head are the same as in part
(d). What then is the force F exerted by the hammer head on the nail while the hammer head is in contact with the nail and moving downward?
1 answer:
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Answer:
The acceleration of the proton is 9.353 x 10⁸ m/s²
Explanation:
Given;
speed of the proton, u = 6.5 m/s
magnetic field strength, B = 1.5 T
The force of the proton is given by;
F = ma = qvB(sin90°)
ma = qvB
where;
m is mass of the proton, = 1.67 x 10⁻²⁷ kg
charge of the proton, q = 1.602 x 10⁻¹⁹ C
The acceleration of the proton is given by;
Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²
Answer:
The time it can operate between chargins in minutes is
Explanation:
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