Fnet=fa-fr
=47-23
=24n
W=F∆Xcos°
=24n×0.025cos0
=0.6J
The answer is observation
First the aceleration:
Vf² = Vo² - 2ad
a = (Vf² - Vo²) / 2d
a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m
a = -2,25 m²/s² / 0,8 m
a = -2,81 m/s²
Now, for the net force, use 2nd law of Newton:
F = ma
F = 3,5 kg * (-2,81 m/s²)
F = -9,835 N
The force for stop the bowling ball is <u>-9,835 Newtons.</u>
Answer:
α = 
Explanation:
Applying the equations of motion to determine angular acceleration of the unit,
The sum of moments about O is equal to the product of angular acceleration and moment of inertia
∑Mo = Io*α
Taking the anticlockwise direction as positive moment,
= ( -(1150) + (1400) ) * (0.5 / 2) + ( (475) - (650) ) * (0.3 / 2) - F = Io*α
= 36.5 - (2.5 N.m) =
*α
NOTE: moment of inertia of the pulleys in this instance = 
Hence, 33.75 =
* α
Solving, α = 
<span>b. It ensures that measurements are taken from two points
that are very far apart.
Measurements taken six months apart are the farthest apart
that an astronomer can ever get ... they're on opposite sides
of the Earth's orbit !</span>