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solmaris [256]
3 years ago
9

A science class has a total of 44 students. The number of females is 16 less than the number of males. How many males and how ma

ny females are in the class?
Number of males:
Number of females: ​

Thank you very much ❤️ please answer ASAP
Mathematics
1 answer:
kogti [31]3 years ago
6 0

Answer:

Number of males: 30

Number of females: 14

Step-by-step explanation:

Let x be the number of males

Males: x

Females: x - 16

x + x - 16 = 44

2x = 44 + 16

2x = 60

x = 30

Males: 30

Females 30 - 16 = 14

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Answer:

(1, -2)

Step-by-step explanation:

midpoint x = (x₁ + x₂) / 2

midpoint y = (y₁ + y₂) / 2

(\frac{-1 + 3}{2} , \frac{2 + -(6)}{2} )

  = (1, -2)

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What is the average rate of change of f over the interval [-1, 4] Give an exact number.
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Answer:

  1.4

Step-by-step explanation:

The average rate of change is the "rise" divided by the "run".

  rise/run = (f(4) -f(-1))/(4 -(-1)) = (0 -(-7))/(4+1)

  rise/run = 7/5 = 1.4

The average rate of change on the interval [-1. 4] is 1.4.

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3 years ago
The area, A, of a triangle is 15.3 square centimeters. Its base, b, is
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Answer:

Questions 13-15 will all be related to the same situation.

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Which equation accurately represents this situation?

Step-by-step explanation:

8 0
3 years ago
Russell and Aaron can build a shed in 8 hours when working together. Aaron works three times as fast as Russel. How long would i
Whitepunk [10]

Answer:

32 hours.

Step-by-step explanation:

Let x represent the time taken by Russell and Aaron to build the shed.

We have been given that Russell and Aaron can build a shed in 8 hours when working together. Aaron works three times as fast as Russel.

Russell's work rate would be \frac{1}{x}.

Since Aaron works three times as fast as Russel, so Aaron's work rate would be \frac{3}{x}.

Part of work done by in one hour would be \frac{1}{8}.

We can represent our given information in an equation as:

\frac{1}{x}+\frac{3}{x}=\frac{1}{8}

Let us solve for x.

\frac{1}{x}*8x+\frac{3}{x}*8x=\frac{1}{8}*8x

8+3*8=x

8+24=x

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4 0
3 years ago
a sequence has a first number of 3 and a half common difference of 4 what is the recursive rule of nth term​
ELEN [110]

Answer:

f(n) = f(n-1) + 8 for n > 1

Step-by-step explanation:

Given

f(1) = 3 -- First Term

\frac{1}{2}d = 4 --- half common difference

Required

Find the recursive rule

First, we calculate the common difference

\frac{1}{2}d = 4

Multiply through by 2

2 * \frac{1}{2}d = 2 * 4

d = 8

The second term of the sequence is:

f(2) = 3 + 8 = 11

The third term is:

f(3) = 11 + 8 = 20

So, we have:

f(1) = 3

f(2) = 3 + 8

Substitute f(1) for 3

f(2) = f(1) + 8

Express 1 as 2 - 1

f(2) = f(2-1) + 8

Substitute n for 2

f(n) = f(n-1) + 8

Similarly:

f(3) = 11 + 8

Substitute f(2) for 11

f(3) = f(2) + 8

Express 2 as 3 - 1

f(3) = f(3-1) + 8

Substitute n for 3

f(n) = f(n-1) + 8

Hence, the recursive is:

f(n) = f(n-1) + 8 for n > 1

8 0
3 years ago
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