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givi [52]
3 years ago
9

1- Kilogram is a unit of _____________ in ______________ system ?

Physics
1 answer:
Zanzabum3 years ago
4 0

Answer:

1.The kilogram is the base unit of mass in the International System of Units

2. a caliper

Explanation:

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a water turbine drops water onto a blade which gains ke at water's gpe expense

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3 years ago
Use dimensional analysis to determine how the linear acceleration a in m/s2 of a particle traveling in a circle depends on some,
astraxan [27]

I have to say, i love this kind of problems.

So, we got the linear acceleration, as we all know, linear the acceleration its, in dimensional units:

[a]=[\frac{distance}{time^2}].

Now, we got the radius

[r] = [distance]

the angular frequency

[\omega] = \frac{1}{s}

and the mass

[m]=[mass].

Now, the acceleration doesn't have units of mass, so it can't depend on the mass of the particle.

The distance in the acceleration has exponent 1, and so does in the radius. As the radius its the only parameter that has units of distance, this means that the radius must appear with exponent 1. Lets write

a \propto r.

The time in the acceleration has exponent -2 As the angular frequency its the only parameter that has units of time, this means that the angular frequency must appear, but, the angular frequency has an exponent of -1, this means it must be squared

a \propto r \omega^2.

We are almost there. If this were any other problem, we would write:

a = A r \omega^2

where A its an dimensionless constant. Its common for this constants to appears if we need an conversion factor. If we wanted the acceleration in cm/s^2, for example. Luckily for us, the problem states that there is no dimensionless constant involved, so:

a = r \omega^2

5 0
3 years ago
If the ultimate shear strength of steel is taken to be 3.00 109 Pa, what force is required to punch through a steel plate 1.60 c
photoshop1234 [79]

Answer:

Explanation:

Given

Ultimate shear strength \tau =3\times 10^9\ Pa

thickness of steel Plate t=1.60\ cm

Cross-sectional A=1.20\times 10^2\ cm^2

suppose d is the diameter of cross-section

\frac{\pi }{4}d^2=1.20\times 10^2

d=12.359\ cm

Shear area of circular cross-section

A_s=\pi dt

A_s=\pi \times 12.359\times 1.6

A_s=62.13\ cm^2

Shear Force F_s=A_s\times \tau

F_s=62.13\times 10^2\times 3000

F_s=18.639\ MN  

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3 years ago
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netineya [11]
D) igneous
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An ore.
5 0
4 years ago
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galina1969 [7]

Answer:

D. The state of motion of an object with mass

Explanation:

Specifically, momentum is mv, mass times velocity

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