Answer:
f = 0.84 m
Explanation:
given,
near point of the distance from eye(d_i) = 0.60 m
distance he can read (d_o)= 0.350 m
focal length of the contact lens = ?
now,
Using lens formula
f = 0.84 m
Hence, The focal length of the contact lens that person needed is equal to
f = 0.84 m
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Complete question:
The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 x 10⁻³ m², and the spacing between the plates is 6 x 10⁻³ m. There is no dielectric between the plates. What is the charge on the capacitor?
Answer:
The charge on the capacitor is 1.77nC
Explanation:
Given;
magnitude of electric field between the plates, E = 100 kV/m
Area of each plate, A = 2 x 10⁻³ m²
Distance between the plates, d = 6 x 10⁻³ m
Charge on the capacitor is calculated as;
Q = CV
V = Ed
Therefore, the charge on the capacitor is 1.77nC
9. Force = mass * acceleration.
F = ma
(8) = (1)a
8m/s^2 = a
10. First solve for the kinetic energy of the vehicle:
Kinetic energy = (1/2)mass * velocity^2
KE = (1/2)(1200)(2)^2
KE = 2400J
Now use this value in the equation for work:
Since the car comes to a halt, the work is equal to the kinetic energy.
Work = Force * Displacement
W = Fd
(2400) = F(0.15) Remember to convert cm to m
1.6*10^4 N = F