Answer:
The force is
Explanation:
From the question we are told that
The tangential resistive force is ![F_t = 115 \ N](https://tex.z-dn.net/?f=F_t%20%20%3D%20%20%20115%20%5C%20N)
The mass of the wheel is m = 1.80 kg
The diameter of the wheel is ![d = 50.0 cm = 0.5 \ m](https://tex.z-dn.net/?f=d%20%3D%20%2050.0%20cm%20%20%3D%200.5%20%5C%20m)
The diameter of the sprocket is ![d_c = 8.50 \ cm =0.085 \ m](https://tex.z-dn.net/?f=d_c%20%20%3D%20%208.50%20%5C%20cm%20%3D0.085%20%5C%20m)
The angular acceleration considered is ![\alpha = 4.30\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%204.30%5C%20rad%2Fs%5E2)
Generally the radius of the wheel is
![r = \frac{d}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bd%7D%7B2%7D)
=> ![r = \frac{0.5}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B0.5%7D%7B2%7D)
=> ![r = 0.25 \ m](https://tex.z-dn.net/?f=r%20%3D%200.25%20%5C%20m%20)
Generally the radius of the sprocket is
![r_c = \frac{d_c}{2}](https://tex.z-dn.net/?f=r_c%20%3D%20%5Cfrac%7Bd_c%7D%7B2%7D)
=> ![r_c = \frac{0.085}{2}](https://tex.z-dn.net/?f=r_c%20%3D%20%5Cfrac%7B0.085%7D%7B2%7D)
=> ![r_c = 0.0425 \ m](https://tex.z-dn.net/?f=r_c%20%3D%200.0425%20%5C%20m%20)
Generally the moment of inertia of the wheel is mathematically represented as
![I = m * r^2](https://tex.z-dn.net/?f=I%20%20%3D%20%20m%20%20%2A%20%20r%5E2)
=> ![I = 1.80 * 0.25^2](https://tex.z-dn.net/?f=I%20%20%3D%20%201.80%20%20%2A%20%200.25%5E2)
=> ![I = 1.1125 \ kg \cdot m^2](https://tex.z-dn.net/?f=I%20%20%3D%201.1125%20%5C%20kg%20%5Ccdot%20m%5E2)
Generally the torque experienced by the wheel due to the forces acting on it is mathematically represented as
![\tau = F_c * r_c - F_t * r](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20F_c%20%2A%20%20r_c%20%20-%20%20F_t%20%20%2A%20r%20%20)
Here
is the force acting on the sprocket
So
![\tau = F_c * 0.0425 - 115 * 0.25](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20F_c%20%2A%20%200.0425%20-%20115%20%20%2A%200.25%20%20)
![\tau = 0.0425F_c - 28.75](https://tex.z-dn.net/?f=%5Ctau%20%3D%200.0425F_c%20%20-%20%2028.75%20%20)
Generally the torques that will cause the wheel to move with
is mathematically represented as
![\tau = I * \alpha](https://tex.z-dn.net/?f=%5Ctau%20%20%3D%20%20I%20%20%2A%20%5Calpha)
So
![0.0425F_c - 28.75 = I * \alpha](https://tex.z-dn.net/?f=%200.0425F_c%20%20-%20%2028.75%20%20%3D%20%20%20I%20%20%2A%20%5Calpha%20%20)
Answer:
Explanation:
it is a vector as it has a magnitude and a direction. If it was a scalar quantity it would just have a magnitude and would be 45 m. Acceleration is an example of a vector quantity
Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
Answer:
the answer should be the third statement