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Alex73 [517]
3 years ago
10

Aljan and Bella are both driving from Cleveland to Chicago. Aljan leaves at

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

Step-by-step explanation:

In order to calculate the number of hours, "x", that it'll take for Bella to pass Aljan, we need to find the value of "x" that makes both equations equal. Therefore,

60*x + 20 = 65*x\\65*x - 60*x = 20\\5*x = 20\\x = \frac{20}{5} = 4

In order to calculate the distance they traveled, we must use this value for "x" in any of the equations, as done below:

y = 65*4\\y = 260

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

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4) d) 381.25 m
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4 years ago
Use the distributive property to remove the parentheses.<br> -5(-6y+4x-5)
Vitek1552 [10]

Answer:

Distributive property means to multiply the number outside the parentheses to the numbers & variables inside the parentheses.

-5(-6y+4x-5)

= 30y-20x+25

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3 years ago
Graph the relation and it's inverse. Use open circles to graph the points of the inverse
joja [24]

Step-by-step explanation:

We are given a set of points (0,3), (4,2), (9,7) and (10,-1) representing a function.

It is required to graph the function and its inverse.

As we know that, the inverse of a function is reflected by y=x line on the graph.

So, in order to find the inverse we have to replace the co-ordinate (x,y) by (y,x).

Then the points (3,0), (2,4), (7,9) and (-1,10) represents the inverse of the function.

So, after plotting all the points of the function and its inverse, we get the following graph, where figure 1 is of the function and figure 2 is of its inverse.

3 0
3 years ago
Read 2 more answers
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
A 5th degree polynomial with 3 terms?
larisa86 [58]

Answer:

Hey there. Heres ur answer

Fifth degree polynomials are also known as quintic polynomials. Quintics have these characteristics:

One to five roots.

Zero to four extrema.

One to three inflection points.

6 0
3 years ago
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