The balanced chemical
reaction will be:
C3H8 + 5O2 = 3CO2 +4H2O
We are given the amount of propane gas to be burned. This will be
our starting point.
<span>38.95 </span><span>g C3H8 ( 1 mol C3H8 / 44.1 g C3H8 ) ( 5 mol O2/1
mol C3H8)(32 g O2 / 1 mol O2) =141.32 g O2
Therefore, the reaction consumes approximately 142 grams of oxygen gas.</span>
Answer:
63.55 amu
Explanation:
(0.692 * 62.930) + (0.308 * 64.928) = 63.55 amu
Copper has two naturally occurring
isotopes: copper-63 (69.17%) and
copper-65 (30.83%).
Calculate the average atomic mass of
copper if the relative masses of the
isotope are copper 63 (62.93 amu)
and copper-65 (64.93 amu).
Cu-63 (0.6917 x 62.93 amu)
Cu-65 + (0.3083 x 64.93 amu)
Avg. mass = 63.55 amu
The indivisibility of an atom was proved wrong: an atom can be further subdivided into protons, neutrons and electrons.
The complete reaction is as,
4-Aminophenol + Acetic Anhydride → <span>Acetaminophen + Acetic Acid
First of all convert the ml of Acetic anhydrite to grams,
As,
Density = mass / volume
Solving for mass,
mass = Density </span>× Volume
<span>Putting values,
mass = 1.08 g/ml </span>× 5ml
<span>
mass = 5.4 g of acetic anhydride
First Find amount of acetic anhydride required to react completely with 2 g of p-Aminophenol,
As,
109.1 g of p-aminophenol required = 102.1 g of acetic anhydride
so, 2 g of p-aminophenol will require = X g of Acetic Anhydride
Solving for X,
X = (2 g </span>× 102.1 g) ÷ 109.1 g
X = 1.87 g of acetic anhydride is required to be reacted.
But, we are provided with 5.4 g of Acetic Anhydride, means p-aminophenol is the limiting reactant and it controls the formation of product. Now Let's calculate for product,
As,
109.1 g of p-aminophenol produced = 180.2 g of <span>Acetaminophen
So 2.00 g of p-aminophenol will produce = X g of Acetaminophen
Solving for X,
X = (2.00 g </span>× 180.2 g) ÷ 109.1 g
X = 3.30 g of Acetaminophen
Result:
<span>If 2.00g of p-aminophenol reacts with 5.00 ml of acetic anhydride 3.30 g of acetaminophen is made.</span>
