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3 years ago

Which model shows 6 electrons in the outer shell of the atom?

Chemistry

2 answers:

AVprozaik [17]3 years ago

7 0

D. Model number 2

Hope this helps!! (:

fgiga [73]3 years ago

5 0

Answer:

2 has 6 on the outer shell

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One and a half gallons of paint are used on refrigeration units which are then baked dry in a 275F oven for 2 hours. If the pain

brilliants [131]

Answer:

Hence the evaporation rate in pints per minute is 0.001583.

Explanation:

Now,

1.5 gallons of paint are used.

It has 5% solid, so total 95% of 1.5 gallon can evaporate(only the solvent part will evaporate).

95% of 1.5 gallon=(95/100)*1.5 = 1.425 gallons.

1gallon = 8 pints.

So 1.425 gallons=8*1.425 pints

=11.4 pints.

Evaporation requires 2 hours. That is 3600*2 seconds = 7200 seconds.

So evaporation rate= 11.4 pints/7200 seconds.

=0.001583 pints per second

4 0

3 years ago

Which probe should be used to check the temperature of a chicken breast?

Eddi Din [679]

Answer:

penetration probe

Explanation:

it is a penetration probe

8 0

2 years ago

Which of these molecules has an overall dipole moment? O A. F2 B. H2S C. CH4 D. CO2

adelina 88 [10]

Answer:

i think the answer is B cus i think of that

4 0

3 years ago

A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin

lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, $3.0\times 10^1g$

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of iron metal = $0.45J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of iron metal = 32.3 g

$m_2$ = mass of water = ?

$T_f$ = final temperature of mixture = $59.2^oC$

$T_1$ = initial temperature of iron metal = $21.9^oC$

$T_2$ = initial temperature of water = $63.5^oC$

Now put all the given values in the above formula, we get

$32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC$

$m_2=30.16g\approx 3.0\times 10^1g$

Therefore, the mass of the water in two significant figures is, $3.0\times 10^1g$

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3 years ago

I am fueled by the warm water of the ocean. As the warm water evaporates it rises until there is an enormous amount of heated mo

DedPeter [7]

It's a definitely a hurricane.

8 0

3 years ago