Explanation:
Molar mass of is 94 g/mol. As it is known that number of moles is equal to mass of a substance divided by its molar mass.
Then, calculate the number of moles as follows.
No. of moles = in 1 s
= 0.914 mol
So, in 60 sec number of moles will be equal to 0.914 x 60 = 54.89 mol/min.
Hence, the molar flow rate = 54.89 mol/min
Also, density is equal to mass of a substance divided by its volume.
Density =
Volume =
=
= 80.941
As, 80.941 of volume flows in 1 s
. Therefore, flow of volume in 1 hour will be calculated as follows.
In 1 hr = 80.941
= 291388.24
Since, 1 = 0.001 L.
So, 291388.24
= 291.38824 L/hr
Thus, we can conclude that molar flow rate in mol/min is 54.89 mol/min and the volumetric flow rate in L/hr is 291.38824 L/hr.
Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.
<span>If the temperature is -265 degrees on mercury at night, the temperature in Fahrenheit in -165 degrees. You get that answer by multiplying the -265 by 5/9.</span>
Answer:
[Ba^2+]= 0.400M
[OH-]= 0.800M
Explanation:
Step 1: Data given
Molarity ofBa(OH)2 = 0.400 M
Ba(OH)2 is a strong electrolyte, so 100 % dissociation
Step 2: The equation
Ba(OH)2 → Ba^2+ + 2OH-
In 1 mol Ba(OH)2 we have 1 mol Ba^2+ and 2 moles OH-
Step 3: Calculate the concentration
[Ba^2+]= 1* 0.400 M = 0.400M
[OH-]= 2*0.400 M = 0.800M