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ivanzaharov [21]
3 years ago
14

Great Harvest Bakery purchased bread ovens from New Morning Bakery. New Morning Bakery was closing its bakery business and sold

its two-year-old ovens at a discount for $690,000. Great Harvest incurred and paid freight costs of $30,000, and its employees ran special electrical connections to the ovens at a cost of $4,000. Labor costs were $32,800. Unfortunately, one of the ovens was damaged during installation, and repairs cost $4,000. Great Harvest then consumed $800 of bread dough in testing the ovens. It installed safety guards on the ovens at a cost of $1,400 and placed the machines in operation.
Prepare a schedule showing the amount at which the ovens should be recorded in Great Harvest’s Equipment account.
Business
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:

$759,000

Explanation:

Preparation of a schedule showing the amount at which the ovens should be recorded in Great Harvest’s Equipment account.

Purchase price 690,000

Add Freight costs 30,000

Add Electrical connection 4,000

Add Labor costs 32,800

Add Bread dough used in testing the oven 800

Add Safety Guards 1,400

Total cost of equipment $759,000

Therefore the amount at which the ovens should be recorded in Great Harvest’s Equipment account will be $759,000

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Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile r
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Answer:

a)  0.1728

b)  0.09183

c) 0.7354

d) $ 222.25

Explanation:

Given

mean = \mu = $367

Standard deviation = \sigma =$88

Cost of automobile repair is normally distributed.

a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function,   P( x <= x ) = NORMDIST (x,  \mu, \sigma, 1 )

P( x > 450 )   = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b)  P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

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Using Excel, = NORMINV ( Probability, \mu, \sigma )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

8 0
3 years ago
240 individuals are recruited in this trial, and the new treatment is effective on 60 of them. What is the p-value associated wi
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Answer:

Explanation:

Experiments were performed for 240 people, 60 people test positive.

Step 1: we calculate the sample proportion; p= 60/240= 0.25.

Step 2: calculate the standard error for the sample, which is the square root of sample proportion,p = p(1-p)/n, n=100

0.25(1-0.25)/100

= 0.04.

Step 3: calculate the test statistics; assuming the hypothesis test percentage is 25%

Then, we say 0.25-1=0.75

-0.75/0.04

= -1.875.

In particular, the sample results are -1.875 standard error.

Probability of Z is less than -1.875.

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3 0
3 years ago
Absent any exaggeration, supply chain professionals could boast how crucial their role is in satisfying B2B and B2C customers al
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Answer:

True, but it applies to everyone in the organization.

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Modern companies can only be successful if every single employee works as a team member, since competition keeps increasing and customers' expectations keep rising.

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We tend to believe that what we do is extremely important and difficult to do, and other people have it easier because their are simpler than ours. But that is just nonsense. Once I heard a quarterback talking about who was the most important player in a football team, and his answer really surprised me, "Quarterbacks fill stadiums, but defenses earn championships". On a team no one is more important, the chain breaks on its weakest link.  

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Answer:

$5,175

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As we know that

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Interest rate = 5.25%

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3 years ago
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