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attashe74 [19]
3 years ago
9

The ground temperature at an airport is 14 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g

round. What is the temperature outside a plane flying at an altitude of 5 kilometers? The temperature outside a plane flying at an altitude of 5 kilometers is °C.
Mathematics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

-13 celsius

Step-by-step explanation:

5.4 * 5 = 27 degrees drop

14-27= -13

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Read the part of a letter. Dear Nana, I am so glad you came to our house for dinner on Sunday, and I appreciate your kind birthd
Zina [86]

Answer:

A) it is a friendly letter written to express thanks

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
g find all the values of p for which the following functions are improperly integrable on the indicated domain. be sure to prove
mel-nik [20]

Answer:

1. In order to make the integral improper  p  must be 1.

2. In order to make the integral improper  p  must be 1.  

Step-by-step explanation:

Using the rules of integration we get that for

f(x)= \frac{1}{x^p}

\int\limits_{0}^{1}  \frac{1}{x^p}  \, dx  = \frac{x^{1-p}}{(1-p)}  \, |\limits_{0}^{1}   = \frac{1}{1-p} - 0 = \frac{1}{1-p}

Therefore in order to make that integral improper  p  must be 1.

If  p = 1     then you would have a 1/0  indeterminate form.

2.   Using the of integration, specifically substitution we get that for

f(x) = \frac{1}{x(ln(x)^p)}

\int\limits_{e}^{\infty} \frac{1}{x(ln(x))^p} \, dx  = \frac{(ln(x))^{1-p}}{1-p} \, |\limits_{e}^{\infty}

For   p \geq 1  we would have

\int\limits_{e}^{\infty} \frac{1}{x(ln(x))^p} \, dx  = \frac{1}{p-1}

And the problem is the same.  If  p=1   we would have a 1/0 indeterminate form.

5 0
3 years ago
In Exploration 5.4.2 Question 2, what conclusion can you make about the value of the derivative at
givi [52]

The value of the derivative at the maximum or minimum for a continuous function must be zero.

<h3>What happens with the derivative at the maximum of minimum?</h3>

So, remember that the derivative at a given value gives the slope of a tangent line to the curve at that point.

Now, also remember that maximums or minimums are points where the behavior of the curve changes (it stops going up and starts going down or things like that).

If you draw the tangent line to these points, you will see that you end with horizontal lines. And the slope of a horizontal line is zero.

So we conclude that the value of the derivative at the maximum or minimum for a continuous function must be zero.

If you want to learn more about maximums and minimums, you can read:

brainly.com/question/24701109

4 0
2 years ago
So this has to do with permutations and honestly I need an explanation on how I can figure these out.
AnnZ [28]
Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24

hence 24 is the correct answer....


u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....

as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.



I know this is pretty much confusing ....but still I tried my best....

if anything troubles u here feel free to ask me
6 0
3 years ago
There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red
madam [21]

Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =\frac{12}{20}

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =\frac{8}{19}

So, the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag =\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}

Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

3 0
4 years ago
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