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Agata [3.3K]
3 years ago
7

A wire of radius 0.8 cm carries a current of 106 A that is uniformly distributed over its cross-sectional area. Find the magneti

c field B at a distance of 0.07 cm from the center of the wire.
Physics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

The magnetic field is B =  2.319 *10^{-3} \  T

Explanation:

From the question we are told that

   The radius of the wire is r = 0.8 \ cm = 0.008 \  m

    The current is I  =  106 \  A

    The position considered is  d = 0.07 cm = 0.0007 m

 Generally the magnetic field is mathematically represented as

         B =   \frac{\mu_o * I}{2\pi * \frac{r^2}{d} }

Here \mu_o is the permeability of free space with value 4\pi * 10^{-7} N/A^2

So    

        B =   \frac{ 4\pi * 10^{-7} * 106 }{2 * 3.142  * \frac{0.008^2}{0.0007} }

=>     B =  2.319 *10^{-3} \  T

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sleet_krkn [62]

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a)   I = 1,894 10¹⁰ W / m², b)  E = 1.376 10⁵ N / C

Explanation:

a) intensity is defined as energy per unit area per unit time

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let's reduce the magnitudes to the SI system

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the laser area is

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4 0
3 years ago
An inductor carries a current of 1.6 a, and the magnetic energy stored in the inductor is 0.0020 j. what is the inductance
faltersainse [42]
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8 0
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Answer:

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We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

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Object 2 (we will make this one negative as it is travelling in the opposite direction):
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