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nekit [7.7K]
2 years ago
13

The Intensity of solar radiation at the Earth's orbit is 1370 W/m2. However, because of the atmosphere, the curvature of the Ear

th, and rotation (night and day), the actual intensity at the Earth's surface is much lower. At this moment, let us assume the intensity of solar radiation is 750 W/m2. You have installed solar panels on your roof to convert the sunlight to electricity. A) If the area of your solar panels is 4 m2, How much power is incident on your array? Watts Submit Answer Tries 0/2 B) Unfortunately, solar panels are only about 20% efficent... Only 1/5 of the light is converted to electricity. This being the case, how much electrical power are you actually producing for your home at this moment?
Physics
2 answers:
Otrada [13]2 years ago
3 0

Answer:

A. Power incident on panel = 3000W

B. Electrical power generated = 600W

Explanation:

Actual solar intensity I = 750W/m2

A) if area A of panel = 4m2, then,

Power incident on panel = I x A

P = 750 x 4 = 3000W

B) if panel efficiency is 20%,

Then,

Power generates = 0.2 x 3000 = 600W of electricity.

Svet_ta [14]2 years ago
3 0

Answer:

a) 3000W

b) 600W

Explanation:

A) To solve this problem we have to use

P=IA

where I is the intensity of light and A is the area of our solar panels. By replacing we have

P=(750\frac{W}{m^2})(4m^2)=3000W

B) However we know that the panel only absorb 20% of the total power. Hence we have that the real power is

P_r=0.2IA=0.2(3000W)=600W

HOPE THIS HELPS!!

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Answer:

6 days.

Explanation:

From radioactivity, The expression for half life is given as,

R/R' = 2⁽ᵃ/ᵇ)................... Equation 1

Where R = original mass of the radioactive substance, R' = Remaining mass of the radioactive substance after decay, a = Total time taken to decay, b = half life.

Given: R = 80 g, R' = 10 g, b = 2 days.

Substitute into equation 1

80/10 = 2⁽ᵃ/²⁾

8 = 2⁽ᵃ/²⁾

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Equating the base and solving for a

3 = a/2

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5 0
3 years ago
On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small
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When the surface of the comb rubs on your hair, the comb is electrically charged. When the comb comes close to the paper, the charge on the comb causes charge separation on the paper bits. Since paper is neutral, positive and negative charges are equivalent. The charge on the comb charges the area of the bit of paper nearest the comb to the opposite. Thus, the bits of paper become attracted to the comb.
5 0
2 years ago
You are removing branches from your roof after a big storm. You throw a branch horizontally from your roof, which is a height 3.
mart [117]

Answer:

The initial velocity in the x-direction with which the branch was thrown is approximately 10.224 m/s

Explanation:

The given parameters of the motion of the branch are;

The height from which the branch is thrown = 3.00 m

The horizontal distance the branch lands from where it was thrown, x = 8.00 m

The direction in which the branch is thrown = Horizontally

Therefore, the initial vertical velocity of the branch, u_y = 0 m/s

The time it takes an object in free fall (zero initial downward vertical velocity) to reach the ground is given as follows;

s = u_y·t + 1/2·g·t²

Where;

u_y = 0 m/s

s = The initial height of the object = 3.00 m

g = The acceleration due to gravity = 9.8 m/s²

∴ s = 0·t + 1/2·g·t² = 0 × t + 1/2·g·t² = 1/2·g·t²

t = √(2·s/g) = √(2 × 3/9.8) = (√30)/7 ≈ 0.78246

The horizontal distance covered before the branch touches the ground, x = 8.00 m

Therefore, the initial velocity in the horizontal, x-direction with which the branch was thrown, 'uₓ', is given as follows;

uₓ = x/t = 8.00 m/((√30)/7 s)

Using a graphing calculator, we get;

uₓ = 8.00 m/((√30)/7 s) = (28/15)·√30 m/s ≈ 10.224 m/s

The initial velocity in the horizontal, x-direction with which the branch was thrown, uₓ ≈ 10.224 m/s.

3 0
3 years ago
What is called gravity ​
Harrizon [31]
Gravity is also called gravitation
3 0
3 years ago
Your starship, the Aimless Wanderer,lands on the mysterious planet Mongo. As chief scientist-engineer,you make the following mea
melisa1 [442]

Answer:

m = 1.26*10²⁵ kg.

Explanation:

Assuming that the mass of the stone is much smaller than the mass of the planet, we can get the mass, applying the Universal Law of  Gravitation to both masses, as follows:

Fg = G* ms* mp / rp²

Now, if we apply Newton's 2nd Law to the mass of the stone, we can get the gravitational acceleration, as follows:

Fg = ms*a = ms*g ⇒ g = G*mp / rp²

First of all, we need to get the value of g.

Assuming that this acceleration is constant, we can appy the kinematic equations to this situation.

We know that the stone is thrown upward with an initial velocity vo = 15 m/s.

At the highest point in the trajectory, just before of changing direction, the stone comes momentarily to a stop.

At this point, applying the definition of acceleration, we can write:

vf = vo -g*t ⇒ 0 = vo -gt ⇒ g = vo/t (1)

We have the total time since the stone was thrown upwards, not the one used for the upward trajectory.

It can be showed, using the expression for the displacement (which is the same in both directions) that the time used for going up, it's the same used to go down, so the time that we need to put in (1). is just the half of the total time.

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g = 15 m/s / 4.5 s = 3.33 m/s²

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g=G*mp / rp² (2)

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Assuming that it's a perfect sphere, we can get this value from the value of the circumference at the planet's equator:

rp = 2*π*rp / 2*π ⇒ rp = 1.0*10⁵ km / 2*π = 15,915 km.

With this value for  rp, we can solve (2) for mp, as follows:

mp= g*rp² / G = 3.33 m/s² * (15,915 km)² / 6,67*10⁻¹¹ N.m²/kg²

mp = 1.26*10²⁵ kg.

8 0
3 years ago
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