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3 years ago

sticking your fingers into a wall socket will not bring you into direct contact with an electrical current. true or false

Physics

2 answers:

hram777 [196]3 years ago

7 0

Answer:

False

Explanation: Sticking fingers into a wall socket will bring us into direct contact with an electrical current because human body is a conductor of electricity. Effect of electric current is visible when circuit of flow is complete. In this case when we touch live wire or socket human body complete its circuit and get an electric shock. Sometimes this can be avoided by wearing footwear made up of insulator.

SCORPION-xisa [38]3 years ago

3 0

The correct answer is false cause how can u fit your finger in a wall something it's to small

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2 years ago

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3 years ago

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3 years ago

two charges having the same charge magnitude experiencing an attracting force of 3.60N when the charges are 30cm apart.what is t

Tomtit [17]

The charges have opposite sign and magnitude $6 \mu C$

Explanation:

The magnitude of the electrostatic force between two electric charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, we have:

F = 3.60 N is the force between the two charges

r = 30 cm = 0.30 m is their separation

The two charges have same magnitude, so

$q_1 = q_2 = q$

So we can rewrite the equation as

$F=\frac{kq^2}{r^2}$

And solving for q:

$q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(3.60)(0.30)^2}{8.99\cdot 10^9}}=6\cdot 10^{-6} C = 6\mu C$

Moreover, the force between the charges is attractive: we know that charges of same sign repel each other while charges of opposite sign attract each other, therefore the charges in this problem have opposite sign, so

$q_1 = 6 \mu C\\q_2 = -6 \mu C$

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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