Question

A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon is in the cylinder?

Answer 1

Answer:

n=28.03

Explanation:

For this problem you would have to use the Ideal gas law formula which is $PV=nRT$. In this formula, R is called the ideal gas law constant which is R= 0.08205

For your problem, this formula would look like this...$n=\frac{PV}{RT}$

First you would have to convert Celsius to Kelvin:   273 + 127 C= 400K

Your problem would look like this in the formula $n= \frac{(18.4 atm)(50.0 L)}{(0.08205)(400 K)}$

Once solved n= 28.03 mol