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CaHeK987 [17]
3 years ago
15

A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon is in the cylinder?

Chemistry
1 answer:
olasank [31]3 years ago
7 0

Answer:

n=28.03

Explanation:

For this problem you would have to use the Ideal gas law formula which is PV=nRT. In this formula, R is called the ideal gas law constant which is R= 0.08205

For your problem, this formula would look like this...n=\frac{PV}{RT}

First you would have to convert Celsius to Kelvin:   273 + 127 C= 400K

Your problem would look like this in the formula n= \frac{(18.4 atm)(50.0 L)}{(0.08205)(400 K)}

Once solved n= 28.03 mol

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Find your answer in the explanation below.

Explanation:

PV = nRT is called the ideal gas equation and its a combination of 3 laws; Charles' law, Boyle's law and Avogadro's law.

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From, Charles' law, we have that volume is directly proportional to the absolute temperature of the gas at constant pressure. i.e V = T

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