Ask question

Ask question

All categories

3 years ago

6

Mrs. Tomas says that the number of students in her class on this week has no variability. Her student, Pierce, says that it does

have variability because someone could be absent. Do you agree or disagree ? Why or why not

1 answer:

user100 [1]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

There are 4 generations. Daughter, mother, grandma, and great-grandma. The daughter is 44 less than the grandma's age. The great

Snezhnost [94]

Answer:

Age of Grandma = 59 years.

Age of great Grandma = 81 years

Ages of Mother = 38 years

Age of Daughter = 15 years

Step-by-step explanation:

Given:

Total years they all lived = 193

We need to find the ages of all lady.

Solution:

Let the age of grandma be 'x'.

Now Given:

The daughter is 44 less than the grandma's age.

So we can say that;

Age of the Daughter = $x-44$

The great-grandma is 22 more than the grandma's age.

So we can say that;

Age of the great grandma = $x+22$

The mother is 80 less than twice the grandma's age.

So we can say that;

Age of the mother = $2x-80$

Now we can say that;

Total years they all lived is equal to sum of age of grandma, Age of the Daughter, Age of the great grandma, Age of the mother.

framing in equation form we get;

$x+x-44+x+22+2x-80=193\\\\5x-102=193$

Adding both side by 102 we get;

$5x-102+102=193+102\\\\5x= 295$

Dividing both side by 5 we get;

$\frac{5x}{5}=\frac{295}{5}\\\\x= 59\ years$

Hence Age of Grandma = 59 years.

Age of great Grandma = $x+22 =59+22 = 81\ years$

Ages of Mother = $2x-80= 2\times 59-80 = 38\ years$

Age of Daughter = $x-44=59-44=15\ years$

7 0

3 years ago

Help with my math test please

Setler79 [48]

Answer:

The graph shows the proportional relationship between total spent and number of months

A proportional relationship has the following characteristics

In a proportional relationship, the ratio of the 'x' and 'y' values is constant for all data pairs

The rate of change between the two quantities in a proportional relationship is constant

The graph of a directly proportional relationship passes through the origin

Therefore, the significance of the given points are;

1. The point (1, 5) is the first point that indicates the proportional relationship between the 'x' and 'y' values and from which the the constant of proportionality, k = y/x can be found as follows;

When x = 1 month, and y = $ 5, for the proportional relationship, we have;

k = y/x = $ 5/(1 month) = 5 $/month

2. The point (0, 0) is the starting point of the relationship and indicates that the graph of the 'x', and 'y', values passes through the origin and the relationship between the ;x;, and ;y;, values is a directly proportional relationship

3. The point (4, 20) which is the limiting point or the point with the highest 'y' value gives;

1) The total payment after 5 months

2) it can be used to draw the graph of the straight line relationship

3) Provides verification of the constant of proportionality

Step-by-step explanation:

5 0

3 years ago

Lera25 [3.4K]

Answer:

To construct the Square using a compass and straight edge, you have written the steps not in proper order. I am rearranging the steps for you

1. Construct horizontal H J¯¯¯¯¯

2. Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .

3.Label the point of intersection of the two circles above HJ¯¯¯¯¯ , point K, and the point of intersection of the two circles below HJ¯¯¯¯¯ , point L.

4.Construct KL¯¯¯¯¯ , the perpendicular bisector of HJ¯¯¯¯¯ , intersecting HJ¯¯¯¯¯ at point M.

5.Construct a circle with point M as the center with radius MJ .

6.Label the point of intersection of circle M and KL¯¯¯¯¯ closest to point K, point N, and the point of intersection of circle M and KL¯¯¯¯¯ closest to point L, point O.

7.Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .

3 0

3 years ago

The half-life of the radioactive element unobtanium-43 is 10 seconds. If 48 grams of unobtanium-43 are initially present, how ma

natka813 [3]

Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element = 48 grams

half life, t = 10 seconds

time of decay (s) remaining mass of the radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

60------------------------------------------------------0.75 grams

Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

7 0

3 years ago

Jason and his children went into a grocery store and will buy bananas and mangos. Each banana costs $0.90 and each mango costs $

Andrej [43]

Answer:

25 ≥ 0.90b + 2m

Step-by-step explanation:

Given:

Cost of each banana = $0.90

Cost of each mango = $2

Total amount = $25

Find:

Inequality

Computation:

Assume;

Number of banana = b

Number of mango = m

Total amount ≥ Cost of total banana + Cost of total mango

25 ≥ 0.90b + 2m

8 0

3 years ago