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2 years ago

SHOW YOUR WORK/SHOW HOW YOU GOT YOUR ANSWER

Mathematics

1 answer:

Tresset [83]2 years ago

3 0

Add 35 to 140 and then subtract 80 equals $95
35 +140=170 -80
$95

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What is the value of x ? Circle the correct 2.5x=35. <br> X=14 <br><br> X=16

scoundrel [369]

Answer:

All you have to do is divide both sides by 2.5 to find your answer.

2.5x / 2.5 = 35 / 2.5

x = 14

The answer is X = 14.

I hope this helps!

-Mikayla

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3 years ago

2.1 If 5 + 3 = 0 and < 0, evaluate (without using a calculator):

Sergeeva-Olga [200]

1. 18

2.8

3.-1

<h3>What is expression?</h3>

An expression is a set of terms combined using the operations +, – , x or ,/.

Given:

1. 22 − 1 (4)

=22- 1*4

= 22-4

= 18

2. 2 + 2 (3)

=2+2*3

=2+6

3. 1 − 2

= -1

Learn more about expression here:

brainly.com/question/14083225

#SPJ1

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2 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

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Tems11 [23]

I think it is D
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