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Tju [1.3M]
2 years ago
7

SHOW YOUR WORK/SHOW HOW YOU GOT YOUR ANSWER

Mathematics
1 answer:
Tresset [83]2 years ago
3 0
Add 35 to 140 and then subtract 80 equals $95
35 +140=170 -80
$95
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A bus leaves a bus station and picks up two people at the first stop . At the second stop , the bus picks up three more people .
gogolik [260]
The answer is D. The bus picked up people, and the graph is saying it dropped people off.
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3 years ago
which statement best describes why the value of the car is a function of the number of years since it was purchased?
malfutka [58]

Answer:

Each time, t, is associated with exactly one car value, y.

Step-by-step explanation:

3 0
3 years ago
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Solve the absolute value equation:<br><br> |3x+3|=10
yarga [219]

Answer:

  • x = 2.33

Step-by-step explanation:

We know that when there is an absolute value sign, the value inside the bars is always positive.

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  • => 3x = 10 - 3
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Hence, the value of x is 2.33.

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3 years ago
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Given a focus of (4, 5) and directrix of y= -3 , find the equation of the parabola.
andrey2020 [161]
Check the picture below.

notice, the focus point is at 4,5 whilst the directrix line is at y = -3, below the focus point, meaning the parabola is vertical and opening upwards.

keeping in mind that the vertex is "p" distance from either of these fellows, then the vertex is half-way between both of them, notice in the picture, the distance from y = 5 to y = -3 is 8 units, half that is 4 units, thus the vertex 4 units from the focus or 4 units from the directrix, that puts it at (4,1), whilst "p" is 4, since the parabola is opening upwards, is a positive 4 then.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;(y-{{ k}})^2=4{{ p}}(x-{{ h}})&#10;\\\\&#10;\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=4\\&#10;k=1\\&#10;p=4&#10;\end{cases}\implies (x-4)^2=4(4)(y-1)\implies (x-4)^2=16(y-1)&#10;\\\\\\&#10;\cfrac{1}{16}(x-4)^2=y-1\implies \cfrac{1}{16}(x-4)^2+1=y

8 0
3 years ago
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