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2 years ago

How is thermal energy transferred during conduction? Check all that apply.

Chemistry

1 answer:

Dvinal [7]2 years ago

5 0

Answer:

Thermal energy is transferred between particles that are in direct contact with each other.

Thermal energy is transferred between objects of different temperatures.

Thermal energy is transferred from fast-moving particles to slow-moving particles.

Explanation:

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Consider the tables below.

brilliants [131]

The right answer is

Table A Organic solvent

No Perfume No Fuel No Anesthetic No Adhesive Yes

6 0

3 years ago

Read 2 more answers

4. A total of 226 J of heat are absorbed as 58.3 g of lead is heated from 12.0oC to 42.0oC. From this data, what is the specific

Zanzabum

C = Q / M * ΔT

Δf - Δi = 42.0ºC - 12.0ºC = 30.0ºC

C = 226 J / 58.3 * 30.0

C = 226 / 1749

C = 0.129 J/gºC

hope this helps!

6 0

3 years ago

The pka of hf is 3.2 determine the pkb of hf?

Julli [10]

Well, first we must remember that

$pK_{a}+pK_{b}=14$

This is because

$K_{a}*K_{b}=10^{-14}$

$-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14$

So then

$pK_{b}=14-pK_{a}=14-3.2=1.8$

7 0

3 years ago

Read 2 more answers

Match the following items.

navik [9.2K]

Answer:

1. not affected by a magnet 1 liquid

2. mostly space 2 solid

3. flows freely but particles still attract 3 proton

4. positively charged particles 4 gas

5. free to move in all space 5 alpha particles

6. negatively charged particles 6 atoms

7. atoms nearly fixed in space 7 gamma ray 8. helium nucleus 8 electron (beta)

6 0

2 years ago

Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point

xeze [42]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is $89.5^0C$

Explanation:

Elevation in boiling point:

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

$k_b$ = boiling point constant = $2.53^0C/kgmol$

m = molality = 3.70

$T_{solution}-T_{solvent}=i\times k_b\times m$

$T_{solution}-80.1^0C=1\times 2.53\times 3.70$

$T_{solution}=89.5^0C$

Thus the boiling point of a 3.70 m solution of phenol in benzene is $89.5^0C$

8 0

2 years ago