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kkurt [141]
3 years ago
15

P and Q are two substances such that the melting point of P and the boiling point of Q are the same. If P is a solid at a certai

n temperature, what state will Q be in at the same temperature?
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

Explanation:

Firstly, it should be noted that melting and freezing points are the same. Thus, when a substance melts at a certain temperature, it means it can also start freezing/solidifying at that same temperature. That been said, <u>when the substance P is a solid at a certain temperature, the other compound Q will boil at that same temperature and hence will be a gas at that same temperature</u>.

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Help pleaseee!!!Please explain how evaporation condensation and precipitation are involved in the water cycle
gizmo_the_mogwai [7]

Answer: The water cycle shows the continuous movement of water within the Earth and atmosphere. ... Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow. Water in different phases moves through the atmosphere (transportation).

Explanation:

8 0
3 years ago
Read 2 more answers
I need help with number 8 please help ASAP.
Rzqust [24]

Answer:

33.33% = 33%

Explanation:

MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)

1 mole of MCO3 will produce → 1 mole of CO2

We need to get the number of mole of CO2:

and when we have 0.22 g of CO2, so number of mole = mass / molar mass

Moles = 0.22 g / 44 g/mol = 0.005 mole

Moles of Mg = moles of CO2 = 0.005 mole

Mass of Mg = moles * molar mass

= 0.005 * 84 /mol = 0.42 g

Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100

=33.33 %

8 0
3 years ago
At what temperature would a 1.50 m nacl solution freeze, given that the van't hoff factor for nacl is 1.9? kf for water is 1.86
IRINA_888 [86]
Win to ki ne lei ma ki mna mata ki ss kk
5 0
3 years ago
The inhibition caused by the final end product of a reaction is called
Troyanec [42]

Answer:

Non competitive inhibition

Explanation:

Hello,

During enzymatic catalysis, the active sites could be occupied by the very same products' molecules turning out into an inhibition (the reaction starts to slow down since to active places are available for the reagents to react). Nonetheless this inhibition is not competitive as long as the product does not react due to the active sites it is occupying.

Best regards.

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3 years ago
Solid carbon tetrachloride, CCl4(s), is represented by the diagram above. The attractions between the CCl4 molecules that hold t
Ne4ueva [31]

Hi, you've asked an incomplete question. Here's the diagram that completes the question.

Answer:

<u>(B) nonpolar covalent bonds</u>

Explanation:

This structure in the diagram rightly fits the description of a non-covalent bond because there is an equal sharing of electrons of Carbon (C) and Chlorine (Cl).

<em>Remember</em> too that these elements are in their solid-state, hence the CCl4 (carbon tetrachloride) molecules are held strongly together.

7 0
2 years ago
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