2 1^/4 + 11^/2 = 9^/4 + 3^/2 = 9^/4 + 6^/4 = 15^/4 = 3 3^/4
<h2>
1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:


According to stoichiometry:
1 mole of
will give = 1 mole of 
0.0208 moles of
will give =
of 
Mass of 
Thus 1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
Learn more about molarity
https://brainly.in/question/13034158
#learnwithbrainly
Answer:
cannot be broken down further
Answer: 5. Positive
6. Negative
9. Oxygen carbon hydrogen nitrogen
Explanation:
Answer:
9% solution by mass
Explanation:
If there is 500 gm of solution and 45 g of it is glucose then:
45/500 * 100% = 9 % solution